有没有办法在它所属的DFS树中存储每个顶点的级别?
时间复杂度应为O(|V| + |E|)
。
答案 0 :(得分:0)
这是来自wikipedia的标准DFS伪代码:
1 procedure DFS(G,v):
2 label v as discovered
3 for all edges from v to w in G.adjacentEdges(v) do
4 if vertex w is not labeled as discovered then
5 recursively call DFS(G,w)
添加级别:
1 procedure DFS(G,v,level):
2 label v as discovered
3 v.level = level
4 for all edges from v to w in G.adjacentEdges(v) do
5 if vertex w is not labeled as discovered then
6 recursively call DFS(G,w,level+1)
首先致电DFS(G,v,0)