尝试在画布的javascript中为项目编写n阶bezier。我希望能够让用户按下按钮,在这种情况下' b',以选择每个终点和控制点。到目前为止,我能够在按键上获得鼠标坐标,并使用内置函数制作二次曲线和贝塞尔曲线。我将如何为第n个订单制作代码?
答案 0 :(得分:6)
这是n阶贝塞尔曲线的Javascript实现:
// setup canvas
var canvas = document.getElementById('canvas');
var ctx = canvas.getContext('2d');
canvas.height = window.innerHeight;
canvas.width = window.innerWidth;
ctx.fillText("INSTRUCTIONS: Press the 'b' key to add points to your curve. Press the 'c' key to clear all points and start over.", 20, 20);
// initialize points list
var plist = [];
// track mouse movements
var mouseX;
var mouseY;
document.addEventListener("mousemove", function(e) {
mouseX = e.clientX;
mouseY = e.clientY;
});
// from: http://rosettacode.org/wiki/Evaluate_binomial_coefficients#JavaScript
function binom(n, k) {
var coeff = 1;
for (var i = n - k + 1; i <= n; i++) coeff *= i;
for (var i = 1; i <= k; i++) coeff /= i;
return coeff;
}
// based on: https://stackoverflow.com/questions/16227300
function bezier(t, plist) {
var order = plist.length - 1;
var y = 0;
var x = 0;
for (i = 0; i <= order; i++) {
x = x + (binom(order, i) * Math.pow((1 - t), (order - i)) * Math.pow(t, i) * (plist[i].x));
y = y + (binom(order, i) * Math.pow((1 - t), (order - i)) * Math.pow(t, i) * (plist[i].y));
}
return {
x: x,
y: y
};
}
// draw the Bezier curve
function draw(plist) {
ctx.clearRect(0, 0, canvas.width, canvas.height);
var accuracy = 0.01; //this'll give the 100 bezier segments
ctx.beginPath();
ctx.moveTo(plist[0].x, plist[0].y);
for (p in plist) {
ctx.fillText(p, plist[p].x + 5, plist[p].y - 5);
ctx.fillRect(plist[p].x - 5, plist[p].y - 5, 10, 10);
}
for (var i = 0; i < 1; i += accuracy) {
var p = bezier(i, plist);
ctx.lineTo(p.x, p.y);
}
ctx.stroke();
ctx.closePath();
}
// listen for keypress
document.addEventListener("keydown", function(e) {
switch (e.keyCode) {
case 66:
// b key
plist.push({
x: mouseX,
y: mouseY
});
break;
case 67:
// c key
plist = [];
break;
}
draw(plist);
});
html,
body {
height: 100%;
margin: 0 auto;
}
<canvas id="canvas"></canvas>
这基于this implementation of cubic Bezier curves。在您的应用程序中,听起来您希望使用用户定义的点填充points
数组。
答案 1 :(得分:0)
这是您想要添加的任意数量的点以制作贝塞尔曲线的代码示例。您将传递的点是一个包含点的 x 和 y 值的对象数组。 [ { x: 1,y: 2 } , { x: 3,y: 4} ... ]
function factorial(n) {
if(n<0)
return(-1); /*Wrong value*/
if(n==0)
return(1); /*Terminating condition*/
else
{
return(n*factorial(n-1));
}
}
function nCr(n,r) {
return( factorial(n) / ( factorial(r) * factorial(n-r) ) );
}
function BezierCurve(points) {
let n=points.length;
let curvepoints=[];
for(let u=0; u <= 1 ; u += 0.0001 ){
let p={x:0,y:0};
for(let i=0 ; i<n ; i++){
let B=nCr(n-1,i)*Math.pow((1-u),(n-1)-i)*Math.pow(u,i);
let px=points[i].x*B;
let py=points[i].y*B;
p.x+=px;
p.y+=py;
}
curvepoints.push(p);
}
return curvepoints;
}