在以下工作示例中,如何检索匹配的模型?
S, (cl_3,cl_39,cl_11, me_32,m_59,m_81) =
EnumSort('S', ['cl_3','cl_39','cl_11','me_32','me_59','me_81'])
h1, h2 = Consts('h1 h2', S)
def fun(h1 , h2):
conds = [
(cl_3, me_32),
(cl_39, me_59),
(cl_11, me_81),
# ...
]
and_conds = (And(h1==a, h2==b) for a,b in conds)
return Or(*and_conds)
例如: 作为以下解算器
s = Solver()
x1 = Const('x1', S)
x2 = Const('x2', S)
s.add(fun(x1,x2))
print s.check()
print s.model()
答案 0 :(得分:1)
我假设你想要Z3生成的模型中x1
和x2
的值。如果是这种情况,您可以使用以下方法检索它们:
m = s.model()
print m[x1]
print m[x2]
以下是完整的示例(也可在线获取here)。顺便说一句,请注意我们不需要h1, h2 = Consts('h1 h2', S)
。
S, (cl_3, cl_39, cl_11, me_32, me_59, me_81) =
EnumSort('S', ['cl_3','cl_39','cl_11','me_32','me_59','me_81'])
def fun(h1 , h2):
conds = [
(cl_3, me_32),
(cl_39, me_59),
(cl_11, me_81),
]
and_conds = (And(h1==a, h2==b) for a,b in conds)
return Or(*and_conds)
s = Solver()
x1 = Const('x1', S)
x2 = Const('x2', S)
s.add(fun(x1,x2))
print s.check()
m = s.model()
print m
print m[x1]
print m[x2]