MySQL实现光线投射算法?

时间:2011-09-27 18:22:23

标签: mysql point-in-polygon raycasting

我们需要找到一种快速且相当准确的方法,用于谷歌地图上纬度/经度值和多边形的多边形点。经过一些研究 - 发现了一些关于mysql几何扩展的帖子,并且也实现了 -

SELECT id, Contains( PolyFromText( 'POLYGON(".$polygonpath.")' ) , PointFromText( concat( \"POINT(\", latitude, \" \", longitude, \")\" ) ) ) AS
            CONTAINS
FROM tbl_points
然而,这并不适用于由大量要点组成的多边形:(

经过一些更多的研究 - 遇到了一种称为Ray-casting算法的标准算法,但是在尝试在MySQL中开发查询之前,想要抓住机会,如果有人已经通过了这个或者遇到了一个有用的链接,如何在MySQL / SQL-server中实现该算法。

所以,简而言之 - 问题是:

任何人都可以提供Ray Cast算法的MySQL / SQL服务器实现吗?

其他细节:

  • 多边形是凹面,凸面或复杂的。
  • 目标是快速执行超过100%的准确度。

7 个答案:

答案 0 :(得分:18)

以下功能(MYSQL版本的Raycasting算法)震撼了我的世界:

CREATE FUNCTION myWithin(p POINT, poly POLYGON) RETURNS INT(1) DETERMINISTIC 
BEGIN 
DECLARE n INT DEFAULT 0; 
DECLARE pX DECIMAL(9,6); 
DECLARE pY DECIMAL(9,6); 
DECLARE ls LINESTRING; 
DECLARE poly1 POINT; 
DECLARE poly1X DECIMAL(9,6); 
DECLARE poly1Y DECIMAL(9,6); 
DECLARE poly2 POINT; 
DECLARE poly2X DECIMAL(9,6); 
DECLARE poly2Y DECIMAL(9,6); 
DECLARE i INT DEFAULT 0; 
DECLARE result INT(1) DEFAULT 0; 
SET pX = X(p); 
SET pY = Y(p); 
SET ls = ExteriorRing(poly); 
SET poly2 = EndPoint(ls); 
SET poly2X = X(poly2); 
SET poly2Y = Y(poly2); 
SET n = NumPoints(ls); 
WHILE i<n DO 
SET poly1 = PointN(ls, (i+1)); 
SET poly1X = X(poly1); 
SET poly1Y = Y(poly1); 
IF ( ( ( ( poly1X <= pX ) && ( pX < poly2X ) ) || ( ( poly2X <= pX ) && ( pX < poly1X ) ) ) && ( pY > ( poly2Y - poly1Y ) * ( pX - poly1X ) / ( poly2X - poly1X ) + poly1Y ) ) THEN 
SET result = !result; 
END IF; 
SET poly2X = poly1X; 
SET poly2Y = poly1Y; 
SET i = i + 1; 
END WHILE; 
RETURN result; 
End; 

添加

  DELIMITER ;; 

在函数之前根据需要。 该功能的用法是:

 SELECT myWithin(point, polygon) as result;

,其中

 point  = Point(lat,lng) 
 polygon = Polygon(lat1 lng1, lat2 lng2, lat3 lng3, .... latn lngn, lat1 lng1)

请注意,多边形应该关​​闭(通常情况下,如果您正在检索标准kml或googlemap数据,但只是确保它是 - 请注意lat1 lng1设置在最后重复)

我的数据库中没有点和多边形作为几何字段,因此我必须执行以下操作:

 Select myWithin(PointFromText( concat( "POINT(", latitude, " ", longitude, ")" ) ),PolyFromText( 'POLYGON((lat1 lng1, ..... latn lngn, lat1 lng1))' ) ) as result

我希望这可以帮助某人。

答案 1 :(得分:5)

我会编写一个自定义UDF,用C或Delphi或您使用的任何高级工具实现光线投射算法:

编写UDF的链接
这是MySQL gis实现的源代码,它查找球体上的点(使用它作为模板来查看如何与MySQL中的空间数据类型进行交互)。
http://www.lenzg.net/archives/220-New-UDF-for-MySQL-5.1-provides-GIS-functions-distance_sphere-and-distance_spheroid.html

从MySQL手册:
http://dev.mysql.com/doc/refman/5.0/en/adding-functions.html

MS Visual C ++的UDF教程
http://rpbouman.blogspot.com/2007/09/creating-mysql-udfs-with-microsoft.html

Delphi中的UDF教程:
Creating a UDF for MySQL in Delphi

有关光线投射算法的源代码
伪代码:http://rosettacode.org/wiki/Ray-casting_algorithm
drDobbs中的文章(请注意文章顶部代码的链接):http://drdobbs.com/cpp/184409586
Delphi(实际上是FreePascal):http://www.cabiatl.com/mricro/raycast/

答案 2 :(得分:2)

以防万一,一个接受MULTIPOLYGON作为输入的MySQL函数:http://forums.mysql.com/read.php?23,286574,286574

DELIMITER $$

CREATE DEFINER=`root`@`localhost` FUNCTION `GISWithin`(pt POINT, mp MULTIPOLYGON) RETURNS int(1)
    DETERMINISTIC
BEGIN 

DECLARE str, xy TEXT; 
DECLARE x, y, p1x, p1y, p2x, p2y, m, xinters DECIMAL(16, 13) DEFAULT 0; 
DECLARE counter INT DEFAULT 0; 
DECLARE p, pb, pe INT DEFAULT 0; 

SELECT MBRWithin(pt, mp) INTO p; 

IF p != 1 OR ISNULL(p) THEN 
    RETURN p; 
END IF; 

SELECT X(pt), Y(pt), ASTEXT(mp) INTO x, y, str; 
SET str = REPLACE(str, 'POLYGON((',''); 
SET str = REPLACE(str, '))', ''); 
SET str = CONCAT(str, ','); 

SET pb = 1; 
SET pe = LOCATE(',', str); 
SET xy = SUBSTRING(str, pb, pe - pb); 
SET p = INSTR(xy, ' '); 
SET p1x = SUBSTRING(xy, 1, p - 1); 
SET p1y = SUBSTRING(xy, p + 1); 
SET str = CONCAT(str, xy, ','); 

WHILE pe > 0 DO 
    SET xy = SUBSTRING(str, pb, pe - pb); 
    SET p = INSTR(xy, ' '); 
    SET p2x = SUBSTRING(xy, 1, p - 1); 
    SET p2y = SUBSTRING(xy, p + 1); 

    IF p1y < p2y THEN SET m = p1y; ELSE SET m = p2y; END IF; 

    IF y > m THEN 
        IF p1y > p2y THEN SET m = p1y; ELSE SET m = p2y; END IF; 
        IF y <= m THEN 
            IF p1x > p2x THEN SET m = p1x; ELSE SET m = p2x; END IF; 
            IF x <= m THEN 
                IF p1y != p2y THEN 
                    SET xinters = (y - p1y) * (p2x - p1x) / (p2y - p1y) + p1x; 
                END IF; 
                IF p1x = p2x OR x <= xinters THEN 
                    SET counter = counter + 1; 
                END IF; 
            END IF; 
        END IF; 
    END IF; 

    SET p1x = p2x; 
    SET p1y = p2y; 
    SET pb = pe + 1; 
    SET pe = LOCATE(',', str, pb); 
END WHILE; 

RETURN counter % 2; 

END

答案 3 :(得分:1)

我想在多边形表上使用上面的mywithin存储过程,所以这里是执行此操作的命令。

使用ogr2​​ogr将包含多边形的shapefile导入mysql后,如下所示

ogr2ogr -f "mysql" MYSQL:"mydbname,host=localhost,user=root,password=mypassword,port=3306" -nln "mytablename" -a_srs "EPSG:4326" /path/to/shapefile.shp

然后你可以使用MBRwithin预过滤你的桌子和mywithin完成如下

DROP TEMPORARY TABLE IF EXISTS POSSIBLE_POLYS;
CREATE TEMPORARY TABLE POSSIBLE_POLYS(OGR_FID INT,SHAPE POLYGON);
INSERT INTO POSSIBLE_POLYS (OGR_FID, SHAPE) SELECT mytablename.OGR_FID,mytablename.SHAPE FROM mytablename WHERE MBRwithin(@testpoint,mytablename.SHAPE);

DROP TEMPORARY TABLE IF EXISTS DEFINITE_POLY;
CREATE TEMPORARY TABLE DEFINITE_POLY(OGR_FID INT,SHAPE POLYGON);
INSERT INTO DEFINITE_POLY (OGR_FID, SHAPE) SELECT POSSIBLE_POLYS.OGR_FID,POSSIBLE_POLYS.SHAPE FROM POSSIBLE_POLYS WHERE mywithin(@testpoint,POSSIBLE_POLYS.SHAPE);

创建@testpoint,例如,从

创建
SET @longitude=120;
SET @latitude=-30;
SET @testpoint =(PointFromText( concat( "POINT(", @longitude, " ", @latitude, ")" ) ));

答案 4 :(得分:1)

现在是 MySQL5.6.1 及以上的空间扩展。请参阅function_st-contains上的Docs

答案 5 :(得分:1)

回复zarun函数,在多边形内找到lat / long。

我有一个属性表,有lat / long信息。所以我必须得到其lat / long位于polygon lats / longs(我从Google API获得)中的记录。起初我很愚蠢如何使用Zarun功能。所以这是解决方案查询。

  • 属性
  • 字段: ID,纬度,经度,床位等......
  • 查询:
SELECT id
FROM properties
WHERE myWithin(
    PointFromText(concat( "POINT(", latitude, " ", longitude, ")")),
    PolyFromText('POLYGON((37.628134 -77.458334,37.629867 -77.449021,37.62324 -77.445416,37.622424 -77.457819,37.628134 -77.458334))' )
) = 1 limit 0,50;

希望能为像我这样的傻瓜节省时间;)

答案 6 :(得分:1)

这是一个适用于MULTIPOLYGONS的版本(Zarun的改编版仅适用于POLYGONS)。

CREATE FUNCTION GISWithin(p POINT, multipoly MULTIPOLYGON) RETURNS INT(1) DETERMINISTIC 
BEGIN 
DECLARE n,i,m,x INT DEFAULT 0; 
DECLARE pX,pY,poly1X,poly1Y,poly2X,poly2Y DECIMAL(13,10); 
DECLARE ls LINESTRING; 
DECLARE poly MULTIPOLYGON;
DECLARE poly1,poly2 POINT; 
DECLARE result INT(1) DEFAULT 0; 
SET pX = X(p); 
SET pY = Y(p); 
SET m = NumGeometries(multipoly);
WHILE x<m DO 
SET poly = GeometryN(multipoly,x);
SET ls = ExteriorRing(poly); 
SET poly2 = EndPoint(ls); 
SET poly2X = X(poly2); 
SET poly2Y = Y(poly2); 
SET n = NumPoints(ls); 
WHILE i<n DO 
SET poly1 = PointN(ls, (i+1)); 
SET poly1X = X(poly1); 
SET poly1Y = Y(poly1); 
IF ( ( ( ( poly1X <= pX ) && ( pX < poly2X ) ) || ( ( poly2X <= pX ) && ( pX < poly1X ) ) ) && ( pY > ( poly2Y - poly1Y ) * ( pX - poly1X ) / ( poly2X - poly1X ) + poly1Y ) ) THEN 
SET result = !result; 
END IF; 
SET poly2X = poly1X; 
SET poly2Y = poly1Y; 
SET i = i + 1; 
END WHILE; 
SET x = x + 1;
END WHILE;
RETURN result; 
End;