Agda，with关键字和refl

Question

TL；我想要的DR：

f with g
f | constructor1 val = {!!}

在该目标的背景下，如何获得g ≡ constructor1 val类型的东西？

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我对平等的定义如下：

data _≡_ {a} {A : Set a} (x : A) : A → Set a where
    refl : x ≡ x

以及函数定义的以下子句（对不起，我在那里没有定义的所有函数；类型很重要，最后只有一个目标是正确的）：

f (negSucc a) (negSucc x) c d pr with (negSucc x +Z nonneg d)
f (negSucc a) (negSucc x) c d pr | nonneg int = identityOfIndiscernablesRight (negSucc a +Z nonneg (succ c)) (nonneg (succ int)) (negSucc x +Z nonneg (succ d)) _≡_ (addNonnegSucc (negSucc a) c int pr) (equalityCommutative (addNonnegSucc (negSucc x) d int {!refl!}))

孔的类型必须为negSucc x +Z nonneg d ≡ nonneg int。

但是，即使refl子句将nonneg int定义为等于with，negSucc x +Z nonneg d也不会在那里进行类型检查。