Question

Harris角点探测器

我想用python实现哈里斯角点检测器的方法，但我卡住了请给出一些建议。我已经实现的方法可以找到HERE

/**
  * {@inheritDoc}
  */
public function setDn($dn){
    $this->dn = $dn;
}

/**
  * {@inheritDoc}
  */
public function getDn(){
    return $this->dn;
}

这是我想做的事情的例子：harris exempe

Answer 1

def Harris():
    if im == None:
        msg.showerror('error', 'Ouvrire une image')
        return 0
    msg.showinfo('wait', 'Le programme traite l\'image, veuillez patienter')
    global em
    neim = imap1()
    imarr = np.asarray(neim, dtype=np.float64)
    ix = ndimage.sobel(imarr, 0)
    iy = ndimage.sobel(imarr, 1)
    ix2 = ix * ix
    iy2 = iy * iy
    ixy = ix * iy
    ix2 = ndimage.gaussian_filter(ix2, sigma=2)
    iy2 = ndimage.gaussian_filter(iy2, sigma=2)
    ixy = ndimage.gaussian_filter(ixy, sigma=2)
    c, l = imarr.shape
    result = np.zeros((c, l))
    r = np.zeros((c, l))
    rmax = 0
    for i in range(c):
        print('loking for corner . . .')
        for j in range(l):
            print('test ', j)
            m = np.array([[ix2[i, j], ixy[i, j]], [ixy[i, j], iy2[i, j]]], dtype=np.float64)
            r[i, j] = np.linalg.det(m) - 0.04 * (np.power(np.trace(m), 2))
            if r[i, j] > rmax:
                rmax = r[i, j]
    for i in range(c - 1):
        print(". .")
        for j in range(l - 1):
            print('loking')
            if r[i, j] > 0.01 * rmax and r[i, j] > r[i - 1, j - 1] and r[i, j] > r[i - 1, j + 1] \
                    and r[i, j] > r[i + 1, j - 1] and r[i, j] > r[i + 1, j + 1]:
                result[i, j] = 1
    result = np.transpose(result)
    pc, pr = np.where(result == 1)
    base = plt.gca().transData
    rot = transforms.Affine2D().rotate_deg(270)
    plt.plot(pr, pc, 'r', transform=rot + base, linestyle="None", marker="o", markersize=1)
    plt.savefig('harris_test.png')
    root_analy.geometry("1108x553+85+50")
    frame_active.configure(width=1108, height=40)
    # ---------- frame de present l'image filter------------------
    frame_image_fil = Frame(root_analy)
    frame_image_fil.configure(width=500, height=470)
    frame_image_fil.place(x=605, y=42)
    frame_image_fil.configure(borderwidth=2, relief=GROOVE)
    # --------- frame de title de image resultat ---------------
    frame_imgreslt = Frame(root_analy)
    frame_imgreslt.configure(width=500, height=40, bg='#1B3F5D')
    frame_imgreslt.place(x=760, y=512)
    frame_imgreslt.configure(borderwidth=2, relief=GROOVE)
    label_title1 = Label(frame_imgreslt, text='les point d\'intérêt', font=("Courier", 18), bg='#0F2130', foreground="#4F5459")
    label_title1.pack()
    img = open('harris_test.png')
    em = img
    img = img.resize((491, 458), ANTIALIAS)
    img = ImageTk.PhotoImage(img)
    pano = Label(frame_image_fil)
    pano.configure(image=img)
    pano.image = img
    pano.place(x=0, y=0)
    os.remove('harris_test.png')
    return 0

Answer 2

显然，PIL中没有可用于检测图像中角落的直接功能。然而，我找到了THIS LINK。看看它是否适合你。

您最好的选择是使用OpenCV的内置函数，这会产生相当不错的效果。

THIS PAGE提供了另一种使用scikit image python模块

查找角点的方法

哈里斯角落探测器蟒蛇

2 个答案: