Question

使用this PDB file和以下PyMOL代码：

cd /Users/foo/Desktop/
reinitialize
load pdp_4gg6CD1_I.pdb
as cartoon 
select chainI, chain I
select chainC, chain C 
select chainD, chain D 
show sticks, chainI
spectrum count, cyan_red, chainI
color yellow, chain C

我可以制作这张图片：

我想要做的是显示链C中所选残基之间的距离（黄色）与chainI（棒）。

我想要的链C的选定残基是这样的：

[9, 23, 25, 44, 53, 54, 55, 59, 62, 63, 66]

Y    Y   H   W  R   R   F    F   T  N    V

我该怎么做？

Answer 1

让我们使用cmd.iterate来获取选择中的所有原子（链C和链I），并将坐标和原子名写入字典供以后使用。
然后我们可以计算所有原子之间的所有距离，并将最接近的残基和原子名写入两个列表（min_c和min_i）
在最后一步中，我们只需在最近的原子之间绘制距离对象，我们就完成了：）

from math import sqrt

def closestAtoms(list1=[9, 23, 25, 44, 53, 54, 55, 59, 62, 63, 66], list2=[5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17]):
    atoms = {}
    atoms2 = {}

    for r in list1:
        command = "chain C and resi %s" % (r)
        coordinates = {'atoms': []}
        cmd.iterate_state(-1, command, 'atoms.append([x, y, z, name])', space=coordinates)
        atoms[r] = coordinates['atoms']

    for i in list2:
        command = "chain I and resi %s" % (i)
        coordinates = {'atoms': []}
        cmd.iterate_state(-1, command, 'atoms.append([x, y, z, name])', space=coordinates)
        atoms2[i] = coordinates['atoms']

    for i in list2:
        min_dist = 10**3
        for c in list1:
            for cc in atoms[c]:
                for ii in atoms2[i]:
                    dist = sqrt((cc[0] - ii[0])**2 + (cc[1] - ii[1])**2 + (cc[2] - ii[2])**2)
                    if dist < min_dist:
                        min_dist = dist
                        min_c = [c, cc[3]]
                        min_i = [i, ii[3]]
        cmd.distance('dist_%s_%s' % (min_c[0], min_i[0]), 'chain C and resi %s and name %s' % (min_c[0], min_c[1]), 'chain I and resi %s and name %s' % (min_i[0], min_i[1]))

cmd.extend("closestAtoms", closestAtoms)

如何显示Pymol中残基之间的距离

1 个答案: