有人可以提供一些有关如何解决以下任务的示例/提示/指示:资源可能由两种类型的进程使用:黑色和白色。当白色进程使用资源时,黑色进程不能使用它,反之亦然。实现对资源的访问,避免饥饿。在较旧的帖子中,我被建议使用seqlock算法的变体,但我无法想出如何为此分配调整该算法。
编辑:这是我到目前为止编写的代码
#include <stdio.h>
#include <pthread.h>
#include <sys/wait.h>
#include <unistd.h>
#include <stdlib.h>
struct RW;
struct RW
{
volatile int num_reads_in_progress;
volatile int num_writes;
pthread_cond_t reader_cv;
pthread_cond_t writer_cv;
pthread_mutex_t lock;
};
char *buf;
void signal_next(struct RW *b);
extern char *xx_read(struct RW *);
extern void xx_write(struct RW *, char *);
// Precondition: b->lock must be locked before this function is called
void signal_next(struct RW *b)
{
if (b->num_writes > 0)
{
// if any writes are waiting wake one up
pthread_cond_signal(&b->writer_cv);
}
else
{
// if are no writes pending, wake up all the readers
pthread_cond_broadcast(&b->reader_cv);
}
}
void *ts_read(void *vb);
void *ts_read(void *vb)
{
struct RW *b = vb;
pthread_mutex_lock(&b->lock);
while (b->num_writes > 0)
{
// cond_wait unlocks the mutex, waits to be signaled, then re-acquires the mutex
pthread_cond_wait(&b->reader_cv, &b->lock);
}
// By there b->num_writes must be 0
b->num_reads_in_progress++;
pthread_mutex_unlock(&b->lock);
buf = xx_read(b);
pthread_mutex_lock(&b->lock);
b->num_reads_in_progress--;
signal_next(b);
pthread_mutex_unlock(&b->lock);
return 0;
}
void *ts_write(void *vb);
void *ts_write(void *vb)
{
struct RW *b = vb;
pthread_mutex_lock(&b->lock);
b->num_writes++;
if (b->num_writes > 1 || b->num_reads_in_progress > 0)
{
// cond_wait unlocks the mutex, waits to be signaled,
// then re-acquires the mutex
pthread_cond_wait(&b->writer_cv, &b->lock);
}
pthread_mutex_unlock(&b->lock);
xx_write(b, buf);
pthread_mutex_lock(&b->lock);
b->num_writes--;
signal_next(b);
pthread_mutex_unlock(&b->lock);
return 0;
}
int main(void)
{
pthread_t white[3];
pthread_t black[3];
struct RW *rw;
rw = malloc(sizeof(struct RW));
int i;
for (i = 0; i < 3; i++)
{
pthread_create(&white[i], NULL, &ts_read, &rw);
}
for (i = 0; i < 3; i++)
{
pthread_create(&black[i], NULL, ts_write, &rw);
}
for (i = 0; i < 3; i++)
{
pthread_join(white[i], NULL);
}
for (i = 0; i < 3; i++)
{
pthread_join(black[i], NULL);
}
return 0;
}
答案 0 :(得分:0)
您需要锁定和解锁的互斥锁。基本上,您可以将互斥锁视为布尔值,该值为true或false(如果您愿意,可以锁定或解锁)。
当黑色进程访问资源时,应锁定互斥锁。而且,另一方面,当白色试图访问它时,它应首先检查互斥锁的状态。如果互斥锁的状态被锁定,则必须等到互斥锁被解锁。
伪代码:
unsigned char mutex = 0;
//processBlack tries to access resource
if(mutex == 1)
while(mutex != 0);
mutex = 1;
//now the mutex is unlocked, do whatever you want
mutex = 0; //do not forget to unlock it.
//processWhite tries to access resource
if(mutex == 1)
while(mutex != 0);
mutex = 1;
//now the mutex is unlocked, do whatever you want
mutex = 0; //do not forget to unlock it.
答案 1 :(得分:0)