所以,解释我的代码 - >
我有一个类型为Employee的抽象类,它有自己的字段,例如名称。
然后我从Employee扩展了Admin,Sales和Manager类。这些都有自己的字段,例如admin的fixedBonus,销售的percentBonus和经理的雇员的arraylist。
然后我有一个包含Employees的ArrayList的驱动程序类,因此它包含Admins,Sales和Managers。
我的问题出现在Arraylist元素上。假设我从ArrayList获得了类Admin的员工,并尝试使用getter getFixedBonus()获取他们的fixedBonus字段,我只是不能。我怎样才能做到这一点我可以使用特定于类的getter和setter,而不仅仅是继承的getter和setter?这是我的代码的副本,问题出现了。具体来说,问题出在switch语句的第5和第6例中。
private Employee editAnEmployee(Employee emp) {
boolean exit = false;
boolean validChoice = false;
int choice = 0;
Boolean sure = false; // used in the switch statement
String newName;
double newValue;
Employee admin = new AdminWorker("0", "0", 0, 0, 0); // these are used
Employee sales = new SalesWorker("0", "0", 0, 0, 0, 0); // to check the
Employee manager = new Manager("0", "0", 0, 0); // class of the
// employee
// being sent
// in, to edit
// the fields
// the employee
// may hold
do {
do {
validChoice = true;
emp.toString();
StdOut.println("Which field would you like to edit?");
StdOut.println("1) First Name.");
StdOut.println("2) last Name.");
StdOut.println("3) Hourly rate.");
StdOut.println("4) Hours worked in the last week.");
if (emp.getClass().equals(admin)) {
StdOut.println("5) Fixed Bonus.");
} else if (emp.getClass().equals(sales)) {
StdOut.println("5) Percentage bonus on sales.");
StdOut.println("6) Value of sales made in the last week.");
} else if (emp.getClass().equals(manager)) {
StdOut.println("5) Department.");
}
StdOut.println("0) Exit.");
choice = StdIn.readInt();
if (choice < 0 || choice > 4) {
if (emp.getClass().equals(admin) && choice <= 5) {
validChoice = true;
} else if (emp.getClass().equals(sales) && choice <= 6) {
validChoice = true;
} else if (emp.getClass().equals(manager)) {
validChoice = true;
} else {
StdOut.println("You entered an invalid number! Try Again...");
validChoice = false;
}
}
} while (!validChoice);
switch (choice) {
case 0:
StdOut.println("You are now exiting...");
exit = true;
break;
case 1:
StdOut.println("The employees first name is: " + emp.getFirstName() + ". What would you like the first name to be now?");
newName = StdIn.readString();
StdOut.println("Are you sure you want to change " + emp.getFirstName() + " to " + newName +"?(y/n)");
sure = ynChoice();
if(sure) emp.setFirstName(newName);
break;
case 2:
StdOut.println("The employees last name is: " + emp.getLastName() + ". What would you like the last name to be now?");
newName = StdIn.readString();
StdOut.println("Are you sure you want to change " + emp.getLastName() + " to " + newName +"?(y/n)");
sure = ynChoice();
if(sure) emp.setLastName(newName);
break;
case 3:
StdOut.println("The employees hourly rate is: " + emp.getHourlyRate() + ". What would you like the hourly rate to be now?");
newValue = StdIn.readDouble();
StdOut.println("Are you sure you want to change " + emp.getHourlyRate() + " to " + newValue +"?(y/n)");
sure = ynChoice();
if(sure) emp.setHourlyRate(newValue);
break;
case 4:
StdOut.println("The employee has worked: " + emp.getHoursWorked() + " hours in the last week. What would you like that to be now?");
newValue = StdIn.readDouble();
StdOut.println("Are you sure you want to change " + emp.getHoursWorked() + " to " + newValue +"?(y/n)");
sure = ynChoice();
if(sure) emp.setHoursWorked(newValue);
break;
case 5:
if (emp.getClass().equals(admin)) {
StdOut.println("The employees fixed bonus is: " + emp.getFixedBonus() + ". What would you like that to be now?");
newValue = StdIn.readDouble();
StdOut.println("Are you sure you want to change " + emp.getFixedBonus() + " to " + newValue +"?(y/n)");
sure = ynChoice();
if(sure) emp.setHoursWorked(newValue);
} else if (emp.getClass().equals(sales)) {
StdOut.println("The employees percentage bonus is: " + emp.getPercentageBonus() + ". What would you like that to be now?");
newValue = StdIn.readDouble();
StdOut.println("Are you sure you want to change " + emp.getPercentageBonus() + " to " + newValue +"?(y/n)");
sure = ynChoice();
if(sure) emp.setHoursWorked(newValue);
} else if (emp.getClass().equals(manager)) {
StdOut.println("The employees fixed bonus is: " + emp.getFixedBonus() + ". What would you like that to be now?");
newValue = StdIn.readDouble();
StdOut.println("Are you sure you want to change " + emp.getFixedBonus() + " to " + newValue +"?(y/n)");
sure = ynChoice();
if(sure) emp.setHoursWorked(newValue);
}
break;
case 6:
StdOut.println("The employees sales in the last week are: " + emp.getLastWeeksSales() + ". What would you like that to be now?");
newValue = StdIn.readDouble();
StdOut.println("Are you sure you want to change " + emp.getLastWeeksSales() + " to " + newValue +"?(y/n)");
sure = ynChoice();
if(sure) emp.setHoursWorked(newValue);
break;
}
} while (!exit);
return emp;
}
答案 0 :(得分:3)
我认为 instanceof 关键字在您的情况下可能很有用。
ArrayList<Employee> list; // This is initialized and has Employees
for (Employee person: list) {
if (person instanceof Admin) {
int fixedBonus = ((Admin) person).getFixedBonus();
// Do something here
}
}
这会回答你的问题吗? (你不需要.getClass()。equals(),这就是instanceof的用途:D)
答案 1 :(得分:2)
您应该向员工添加getFixedBonus()
和getPercentBonus()
方法,每个方法返回0.然后其他工作者类可以覆盖它们。
实际上,更好的方法是将其设为interface
并使所有类(包括Employee
)实现interface
。然后,他们可以extend
base
类,它也实现了接口,但提供了默认值。
public static interface Staff {
public double getFixedBonus ();
public double getPercentageBonus ();
public List<Staff> getMinions();
}
// Base class - no bonus by default.
public static class Worker implements Staff {
@Override
public double getFixedBonus() {
return 0;
}
@Override
public double getPercentageBonus() {
return 0;
}
@Override
public List<Staff> getMinions() {
return Collections.EMPTY_LIST;
}
}
public static class Administrator extends Worker implements Staff {
double fixedBonus = 2.13;
@Override
public double getFixedBonus() {
return fixedBonus;
}
}
public static class Salesperson extends Worker implements Staff {
double percentageBonus = 3.14;
@Override
public double getPercentageBonus() {
return percentageBonus;
}
}
public static class Manager extends Worker implements Staff {
List<Staff> minions;
@Override
public List<Staff> getMinions() {
return minions;
}
}
不要被使用instanceof
和投射的黑暗方面所诱惑。你会后悔自己的决定。 oop的重点在于,即使你不知道你正在使用什么样的物体,你仍然可以使用它们。
答案 2 :(得分:0)
使您的客户端代码 lot 更简单(并且更干净 - instanceof和cast难看)的选项是为Employee
中的每个特定方法声明一个默认实现,例如return fixedBonus()
中的Employee
为零,但会在Sales