我有一本这样的字典
{
'S1' :
{
'w1':[ ('a',0), ('b',1), ('c',3)],
'w2':[ ('a',1), ('b',2), ('c',5)],
'w3':[ ('a',1), ('b',1), ('c',4)]
},
'S2' :
{
'w4':[ ('a',1), ('b',2), ('c',5)],
'w5':[ ('a',0), ('b',3), ('c',4)],
'w6':[ ('a',3), ('b',3), ('c',6)]
}
}
我想把它转换成这样的熊猫数据框:
有人可以帮我吗?
答案 0 :(得分:2)
将嵌套列表理解与合并字典一起用于字典列表并传递给 DataFrame
构造函数:
L = [{**{'Col S': k,'Col W':k1}, **dict(v1)} for k, v in d.items() for k1, v1 in v.items()]
df = pd.DataFrame(L)
print (df)
Col S Col W a b c
0 S1 w1 0 1 3
1 S1 w2 1 2 5
2 S1 w3 1 1 4
3 S2 w4 1 2 5
4 S2 w5 0 3 4
5 S2 w6 3 3 6
MultiIndex
的解决方案:
d = {(k, k1): dict(v1) for k, v in d.items() for k1, v1 in v.items()}
df = pd.DataFrame.from_dict(d, orient='index')
print (df)
a b c
S1 w1 0 1 3
w2 1 2 5
w3 1 1 4
S2 w4 1 2 5
w5 0 3 4
w6 3 3 6
然后设置索引名并将MultiIndex
转成列,谢谢@sammywemmy:
df = df.rename_axis(index = ['Col S', 'Col W']).reset_index()
print (df)
Col S Col W a b c
0 S1 w1 0 1 3
1 S1 w2 1 2 5
2 S1 w3 1 1 4
3 S2 w4 1 2 5
4 S2 w5 0 3 4
5 S2 w6 3 3 6