Question

我正在开发2D点并单击冒险，并且在研磨过程中遇到了2D对撞机的问题。

这是游戏的示例场景：

发生了什么事

红色对象：玩家角色。具有一个禁用了运动功能的RigidBody2D和主要运动代码。
绿色背景：是角色移动的环境。使用Box Collider 2D并具有OnGroundClick（）的事件触发器。
紫色对象：是要检测的可交互项。还具有Box Collider 2D和OnInteractableClick（）事件触发器。
主摄像头具有物理二维射线投射器。

这是播放器的代码：

    public NavMeshAgent2D agent;
    public float turnSmoothing = 15f;
    public float speedDampTime = 0.1f;
    public float slowingSpeed = 0.175f;
    public float turnSpeedThreshold = 0.5f;
    public float inputHoldDelay = 0.5f;
    public Rigidbody2D body;
    public bool freezeRotation;
    private WaitForSeconds inputHoldWait;
    private Vector3 destinationPosition;
    private Interactables currentInteractable;
    private bool handleInput = true;

    private const float navMeshSampleDistance = 4f;
    private const float stopDistanceProportion = 0.1f;

    public void OnGroundClick(BaseEventData data)
    {
        Debug.Log("OnGroundClick");
        if (!handleInput)
        {
            return;
        }
        currentInteractable = null;
        PointerEventData pData = (PointerEventData)data;
        NavMeshHit2D hit;
        if (NavMesh2D.SamplePosition(pData.pointerCurrentRaycast.worldPosition,
            out hit, navMeshSampleDistance, NavMesh2D.AllAreas))
        {
            destinationPosition = hit.position;
        }
        else 
        {
            destinationPosition = pData.pointerCurrentRaycast.worldPosition;
        }
        agent.SetDestination(destinationPosition);
        agent.isStopped = false; //agent.Resume();
    }

    public void OnInteractableClick(Interactables interactable)
    {
        Debug.Log("OnInteractableClick");
        if (!handleInput)
        {
            return;
        }
        currentInteractable = interactable;
        destinationPosition = currentInteractable.interactionLocation.position;
        agent.SetDestination(destinationPosition);
        agent.isStopped = false;
    }

注意：NavMesh2D是用于为2D环境创建导航网格物体的第三方资产

我尝试将每个对撞机的z位置更改为无效。

如何分别检测两个对撞机？

Answer 1

我在背景的光线投射器中添加了一些细节。将其移至z轴的最远位置，然后修改其代码。

public void OnGroundClick(BaseEventData data)
{
    Debug.Log("OnGroundClick");
    if (!handleInput)
    {
        return;
    }
    currentInteractable = null;
    PointerEventData pData = (PointerEventData)data;
    Vector3 worldPoint = Camera.main.ScreenToWorldPoint(pData.pointerCurrentRaycast.worldPosition);
    worldPoint.z = Camera.main.transform.position.z;
    Ray ray = new Ray(worldPoint, new Vector3(0, 0, 1));
    RaycastHit2D hitInfo = Physics2D.GetRayIntersection(ray);
    NavMeshHit2D hit;
    if (NavMesh2D.SamplePosition(pData.pointerCurrentRaycast.worldPosition,
        out hit, navMeshSampleDistance, NavMesh2D.AllAreas))
    {
        destinationPosition = hit.position;
    }
    else 
    {
        destinationPosition = pData.pointerCurrentRaycast.worldPosition;
    }
    agent.SetDestination(destinationPosition);
    agent.isStopped = false; //agent.Resume();
}

Unity 2D重叠碰撞器

1 个答案: