从包含字典的python的嵌套列表中创建字典

Question

[{'duration': 634, 'risetime': 1586496046}, 
 {'duration': 473, 'risetime': 1586501927}, 
 {'duration': 608, 'risetime': 1586537843}, 
 {'duration': 536, 'risetime': 1586543678}, 
 {'duration': 577, 'risetime': 1586579648}]

我想用python这个字典列表创建一个字典，即{'duration'：[634，473，608，536，577]，'risetime'：[1586496046，1586501927，1586537843，1586543678，1586579648]

Answer 1

a=[{'duration': 634, 'risetime': 1586496046}, 
  {'duration': 473, 'risetime': 1586501927}, 
  {'duration': 608, 'risetime': 1586537843}, 
  {'duration': 536, 'risetime': 1586543678}, 
  {'duration': 577, 'risetime': 1586579648}]

#Initializing an empty dict
b = {'duration':[],'risetime':[]}
#looping through all values of list 'a' & appending values to respective keys in 'b'
for x in a:
    b['duration'].append(x['duration'])
    b['risetime'].append(x['risetime'])

如果您正在寻找这样的输出：{'duration'：[634，473，608，536，577]， 'risetime'：[1586496046、1586501927、1586537843、1586543678、1586579648]}

Answer 2

这是collections.defaultdict的好用例：

from collections import defaultdict

lst = [
    {'duration': 634, 'risetime': 1586496046}, 
    {'duration': 473, 'risetime': 1586501927}, 
    {'duration': 608, 'risetime': 1586537843}, 
    {'duration': 536, 'risetime': 1586543678}, 
    {'duration': 577, 'risetime': 1586579648}
]

d = defaultdict(list)
for x in lst:
    for k, v in x.items():
        d[k].append(v)

print(d)

输出：

defaultdict(<class 'list'>, {'duration': [634, 473, 608, 536, 577], 'risetime': [1586496046, 1586501927, 1586537843, 1586543678, 1586579648]})

Answer 3

尝试这个：

myList = [{'duration': 634, 'risetime': 1586496046},
 {'duration': 473, 'risetime': 1586501927},
 {'duration': 608, 'risetime': 1586537843},
 {'duration': 536, 'risetime': 1586543678},
 {'duration': 577, 'risetime': 1586579648}]

myDic = {'duration': [], 'risetime':[]}
for x in myList:
    for y in x:
        myDic[y].append(x[y])

print(myDic)

输出

{'duration': [634, 473, 608, 536, 577], 'risetime': [1586496046, 1586501927, 1586537843, 1586543678, 1586579648]}