Question

如何使用python将嵌套列表的列表转换为嵌套字典？

students = [[1, 'John', 'Smith'], [2, 'Anna', 'Jones']]

到

students_dict = {'1': {'name': 'John', 'surname': 'Smith'},
             '2': {'name': 'Anna', 'surname': 'Jones'}}

Answer 1

您可以使用打开包装：

students = [[1, 'John', 'Smith'], [2, 'Anna', 'Jones']]
result = {a:dict(zip(['name', 'surname'], b)) for a, *b in students}

输出：

{1: {'name': 'John', 'surname': 'Smith'}, 2: {'name': 'Anna', 'surname': 'Jones'}}

Answer 2

您的子词典关键字是：

students_dict = {d[0] : dict(zip(keys, d[1:])) for d in students}

通过将键和值（在第一个元素之后）压缩在一起来创建子词典，然后将第一个元素作为键添加到外部字典中：

import tkinter as tk
from tkinter import filedialog
file_path = filedialog.askopenfilename()
print(file_path)
data =  []
data2 = []
data3 = []
flag= False
    with open(file_path,'r') as f:
    for line in f:
        if line.strip().startswith('*NSET, NSET=Nodes_Pushed_Back_IB'):
            flag= True
        elif line.strip().endswith('*NSET, NSET=Nodes_Pushed_Back_OB'):
            flag= False    
        elif flag:          # as long as flag is true append
            data.append(int(line).strip())

从嵌套列表创建嵌套字典

2 个答案: