我有一个字典列表如下，
[{"vehicle_class": "c1", "vehicle_class_count1": 16, "vehicle_usage_count1": 29, "vehicle_usage": "u1", "vehicle_type_count1": 16, "vehicle_type": "t1"}, {"vehicle_class": "c2", "vehicle_class_count1": 11, "vehicle_usage_count1": 29, "vehicle_usage": "u1", "vehicle_type_count1": 11, "vehicle_type": "t1"},{"vehicle_class": "c2", "vehicle_class_count1": 1, "vehicle_usage_count1": 29, "vehicle_usage": "u2", "vehicle_type_count1": 1, "vehicle_type": "t3"},{"vehicle_class": "c3", "vehicle_class_count1": 1, "vehicle_usage_count1": 29, "vehicle_usage": "u2", "vehicle_type_count1": 1, "vehicle_type": "t2"}]
我想从中形成另一个词典列表，如下所示，
[
{
"name": "u1",
"imageURL": "",
"type": "u1",
"children": [
{
"name": "t1",
"imageURL": "",
"type": "t1",
"size": 9221
"children" : [
{"name": "c1",
"imageURL": "",
"type": "c1",
"size": 9221},
{"name": "c2",
"imageURL": "",
"type": "c2",
"size": 9221}
]
}
],
"size": 10393
},
{
"name": "u2",
"imageURL": "",
"type": "u2",
"children": [
{
"name": "t2",
"imageURL": "",
"type": "t2",
"size": 9221,
"children":[
"name": "c3",
"imageURL": "",
"type": "c3",
"size": 9221
]
},
{
"imageURL": "",
"type": "t3",
"name": "t3",
"size": 1058,
"children": [
"imageURL": "",
"type": "c2",
"name": "c2",
"size": 1058
]
}
],
"size": 10393
},
]
这是我到目前为止所尝试过的，我已经完成了预期结果的一半。
result_dict=[] # The above mentioned list comes here
result_list = []
for i in ['vehicle_usage','vehicle_type','vehicle_class']: # This is a hierarchy which I assign here dynamically can contain any number of values.
for item in range(0, len(result_dict)):
for key,value in result_dict[item].items():
if key == i:
if not any(d['name'] == value for d in result_list):
result = {}
result['name'] = value
result['imageURL'] = ''
result['type'] = value
result['size'] = result_dict[item]['%s_count1' % i]
if i != len(result_dict):
result['children'] =[]
print result
result_list.append(result)
print result_list # Final list processed according to the required format.
预期的result_list的顶级词典必须包含vehicle_usage个不同的值，其值分别为vehicle_usage_count1。
第二级（即子列表）将包含第二级等。此数据被发送到需要此格式的d3插件。
级别数量将依赖于值的数量
['vehicle_usage','vehicle_type','vehicle_class']
从我的代码中，所有级别都写入同一级别。我希望他们写到正确的子列表。
答案 0 :(得分：1)
这远非完美，但我认为它正在发挥作用。
datalist = [{"vehicle_class": "c1", "vehicle_class_count1": 16, "vehicle_usage_count1": 29, "vehicle_usage": "u1", "vehicle_type_count1": 16, "vehicle_type": "t1"}, {"vehicle_class": "c2", "vehicle_class_count1": 11, "vehicle_usage_count1": 29, "vehicle_usage": "u1", "vehicle_type_count1": 11, "vehicle_type": "t1"},{"vehicle_class": "c2", "vehicle_class_count1": 1, "vehicle_usage_count1": 29, "vehicle_usage": "u2", "vehicle_type_count1": 1, "vehicle_type": "t3"},{"vehicle_class": "c3", "vehicle_class_count1": 1, "vehicle_usage_count1": 29, "vehicle_usage": "u2", "vehicle_type_count1": 1, "vehicle_type": "t2"}]
levels_index = {1: 'vehicle_usage', 2: 'vehicle_type', 3: 'vehicle_class'}
result = []
def build_node(obj, key):
'''This build the node for your result list'''
return {
'name': obj[key],
'imageURL': '',
'type': obj[key],
'size': obj['%s_count1' % key],
'children': []
}
def build_level(input_list, keyindex):
''' This build one level at a time but call itself recursively'''
key = levels_index[keyindex]
levels_memory = {'vehicle_usage': [], 'vehicle_type': [], 'vehicle_class': []}
output = []
for obj in input_list:
if obj[key] not in levels_memory[key]:
levels_memory[key].append(obj[key])
output.append(build_node(obj, key))
if keyindex < len(levels_index):
output[-1]['children'] = build_level(
[_ for _ in input_list if _[key] == output[-1]['name']],
keyindex + 1)
return output
print build_level(datalist, 1)
这给了我以下输出
[
{
'children': [
{
'children': [
{
'children': [],
'imageURL': '',
'type': 'c1',
'name': 'c1',
'size': 16
}, {
'children': [],
'imageURL': '',
'type': 'c2',
'name': 'c2',
'size': 11
}],
'imageURL': '',
'type': 't1',
'name': 't1',
'size': 16}],
'imageURL': '',
'type': 'u1',
'name': 'u1',
'size': 29
}, {
'children': [{
'children': [],
'imageURL': '',
'type': 't3',
'name': 't3',
'size': 1
}, {
'children': [{
'children': [],
'imageURL': '',
'type': 'c3',
'name': 'c3',
'size': 1
}],
'imageURL': '',
'type': 't2',
'name': 't2',
'size': 1
}],
'imageURL': '',
'type': 'u2',
'name': 'u2',
'size': 29
}
]