Question

我想打印学生的姓名和分数，但我有问题

这是代码

from collections import OrderedDict
from operator import itemgetter

A = 'Ali'
AV = 19.75
M = 'Mohammad'
MV = 19.64
C = 'Cacurs'
CV = 19.50

Name_Ave = {C:CV, M:MV, A:AV}
D = OrderedDict(sorted(Name_Ave.items(), key = itemgetter(1)))


for Keys in D.keys():
    for Values in D.values():
        print('%s Average is: %s' %(Keys, Values))

----这里是外面

Cacurs Average is: 19.5
Cacurs Average is: 19.64
Cacurs Average is: 19.75
Mohammad Average is: 19.5
Mohammad Average is: 19.64
Mohammad Average is: 19.75
Ali Average is: 19.5
Ali Average is: 19.64
Ali Average is: 19.75

我该怎么办？请帮助我

Answer 1

A = 'Ali'
AV = 19.75
M = 'Mohammad'
MV = 19.64
C = 'Cacurs'
CV = 19.50

Name_Ave = {C:CV, M:MV, A:AV}
for item in Name_Ave:
    print(item+' score is : '+str(Name_Ave[item]))

Answer 2

现在，对于D中的每个键，您正在执行的操作是打印字典中的所有值。因此，对于每个学生，您正在遍历字典中所有年级的循环，因此为什么要为每个学生打印每个年级。

应该做的是遍历每个键/值对：

for key, value in D.items():
    print('%s Average is: %s' %(key, value))

Answer 3

解决方案可以是这样的：

from collections import OrderedDict
from operator import itemgetter

A = 'Ali'
AV = 19.75
M = 'Mohammad'
MV = 19.64
C = 'Cacurs'
CV = 19.50

Name_Ave = {C:CV, M:MV, A:AV}
D = OrderedDict(sorted(Name_Ave.items(), key = itemgetter(1)))


for Keys,Values in zip(D.keys(),D.values()):
        print('%s Average is: %s' %(Keys, Values))

@Daniel Mesejo指出，您可以如下更改for周期：

for key, value in D.items():
        print('%s Average is: %s' %(key,value))

Answer 4

我想如果要通过对名称进行排序来打印平均分数，可以只使用sorted（Name_Ave.items（））。

for (name, average) in sorted(Name_Ave.items()): 
    print("The average of {name} is {average}".format(name=name, average=average))

在python3中打印学生姓名和学生分数

4 个答案: