Question

我正在尝试获取学生详细信息的名称。我试过这个代码，但它没有用。请帮帮我。

我想获得学生姓名和部门。

var response = '[
    {
        "student": {
            "id": "12",
                "departmant" :  "computer",
            "created_date": "2015-04-16 12:05:27",
            "modified_date": "2015-04-16 12:05:27"
        },
        "student_details": [
            {
                "id": "2",
                "student_id": "12",
                "lname": "jain",
                "name": "hemant",
                "created_date": "2015-04-16 12:05:27",
                "modified_data": "2015-04-16 12:05:27"
            }
        ]
    }
]';

var codes = jQuery.parseJSON(response);
console.log(codes);
$.each(codes, function (key, value) {
  alert(value.name);
});

Answer 1

JSON应该有效，但您尝试访问的级别太高了。 JSON的结构是

Array(Object(key:value))

您正在尝试访问

Object(key:value)

为了达到你想要的目的，你需要做以下事情：

var codes = jQuery.parseJSON(response);
console.log(codes);
$.each(codes, function (key, value) {
  //key will be 0, since there's only one record in the array
  $.each(value, function (key2, value2) {
       alert(value2.name); // which won't be defined for the first entry (student)
  }
});

或

var codes = jQuery.parseJSON(response);
console.log(codes);
$.each(codes[0], function (key, value) {
  alert(value.name); // which still won't be defined for the first entry (student)
});

或者，更有意义的方式：

var codes = jQuery.parseJSON(response);
console.log(codes);
$.each(codes, function (key, value) {
  alert(value.student.id);
  alert(value.student_details.name);
});

Json回复打印学生姓名

1 个答案: