我需要根据下拉列表A中的选择使用javascript更改下拉列表B的内容。没有涉及数据库查询 - 我事先知道应该在A中选择B的内容。我已经找到了一些使用AJAX的例子,但由于没有涉及数据库查询,所以没有必要。任何人都可以向我指出一些如何做到这一点的示例代码吗?
答案 0 :(得分:44)
function configureDropDownLists(ddl1, ddl2) {
var colours = ['Black', 'White', 'Blue'];
var shapes = ['Square', 'Circle', 'Triangle'];
var names = ['John', 'David', 'Sarah'];
switch (ddl1.value) {
case 'Colours':
ddl2.options.length = 0;
for (i = 0; i < colours.length; i++) {
createOption(ddl2, colours[i], colours[i]);
}
break;
case 'Shapes':
ddl2.options.length = 0;
for (i = 0; i < shapes.length; i++) {
createOption(ddl2, shapes[i], shapes[i]);
}
break;
case 'Names':
ddl2.options.length = 0;
for (i = 0; i < names.length; i++) {
createOption(ddl2, names[i], names[i]);
}
break;
default:
ddl2.options.length = 0;
break;
}
}
function createOption(ddl, text, value) {
var opt = document.createElement('option');
opt.value = value;
opt.text = text;
ddl.options.add(opt);
}
<select id="ddl" onchange="configureDropDownLists(this,document.getElementById('ddl2'))">
<option value=""></option>
<option value="Colours">Colours</option>
<option value="Shapes">Shapes</option>
<option value="Names">Names</option>
</select>
<select id="ddl2">
</select>
答案 1 :(得分:10)
在闭包中使用直接JavaScript设置我的,在评论中提供解释
(function() {
//setup an object fully of arrays
//alternativly it could be something like
//{"yes":[{value:sweet, text:Sweet}.....]}
//so you could set the label of the option tag something different than the name
var bOptions = {
"yes": ["sweet", "wohoo", "yay"],
"no": ["you suck!", "common son"]
};
var A = document.getElementById('A');
var B = document.getElementById('B');
//on change is a good event for this because you are guarenteed the value is different
A.onchange = function() {
//clear out B
B.length = 0;
//get the selected value from A
var _val = this.options[this.selectedIndex].value;
//loop through bOption at the selected value
for (var i in bOptions[_val]) {
//create option tag
var op = document.createElement('option');
//set its value
op.value = bOptions[_val][i];
//set the display label
op.text = bOptions[_val][i];
//append it to B
B.appendChild(op);
}
};
//fire this to update B on load
A.onchange();
})();
<select id='A' name='A'>
<option value='yes' selected='selected'>yes
<option value='no'> no
</select>
<select id='B' name='B'>
</select>
答案 2 :(得分:8)
请你看一下:http://jsfiddle.net/4Zw3M/1/。
基本上,数据存储在数组中,并相应地添加选项。我认为代码说了千言万语。
var data = [ // The data
['ten', [
'eleven','twelve'
]],
['twenty', [
'twentyone', 'twentytwo'
]]
];
$a = $('#a'); // The dropdowns
$b = $('#b');
for(var i = 0; i < data.length; i++) {
var first = data[i][0];
$a.append($("<option>"). // Add options
attr("value",first).
data("sel", i).
text(first));
}
$a.change(function() {
var index = $(this).children('option:selected').data('sel');
var second = data[index][1]; // The second-choice data
$b.html(''); // Clear existing options in second dropdown
for(var j = 0; j < second.length; j++) {
$b.append($("<option>"). // Add options
attr("value",second[j]).
data("sel", j).
text(second[j]));
}
}).change(); // Trigger once to add options at load of first choice