Question

我想创建一个可以在2个不同的表达式变量中存储implies（）函数的左右参数的函数。带有代码的解决方案非常有价值。谢谢。

这是我以前尝试过的东西。

// Open and close ctls.
this.DOM.openCtrl = this.DOM.el.querySelector('.action--menu');
this.DOM.closeCtrl = this.DOM.el.querySelector('.action--close');
this.DOM.ItemcloseCtrl1 = this.DOM.el.querySelector('.item--close1');
this.DOM.ItemcloseCtrl2 = this.DOM.el.querySelector('.item--close2');
this.DOM.ItemcloseCtrl3 = this.DOM.el.querySelector('.item--close3');
this.DOM.ItemcloseCtrl4 = this.DOM.el.querySelector('.item--close4');
this.DOM.ItemcloseCtrl5 = this.DOM.el.querySelector('.item--close5');

this.DOM.openCtrl.addEventListener('click', () => this.open());
this.DOM.closeCtrl.addEventListener('click', () => this.close());
this.DOM.ItemcloseCtrl1.addEventListener('click', () => this.close());
this.DOM.ItemcloseCtrl2.addEventListener('click', () => this.close());
this.DOM.ItemcloseCtrl3.addEventListener('click', () => this.close());
this.DOM.ItemcloseCtrl4.addEventListener('click', () => this.close());
this.DOM.ItemcloseCtrl5.addEventListener('click', () => this.close());

这是输出：

#include<iostream>
#include<string>
#include "z3++.h"
using namespace z3;
using namespace std;

void walk(int tab, expr e)
{
    string blanks(tab, ' ');

    if(e.is_const())
    {
        cout << blanks << "ARGUMENT: " << e << endl;
    }
    else
    {
        cout << blanks << "APP: " << e.decl().name() << endl;
        for(int i = 0; i < e.num_args(); i++)
        {
            walk(tab + 5, e.arg(i));
        }
    }
}

int main()
{
    context c;
    expr x = c.bool_const("x");
    expr y = c.bool_const("y");
    expr z = c.bool_const("z");
    expr e = implies(z,(x && y));
    walk(0, e);
}

Answer 1

我将通过一个示例来表达我的评论

if (e.is_implies()) {
    cout << "left side: " <<endl;
    walk(4, e.arg(0));
    cout << "right side: " <<endl;
    walk(4, e.arg(1));
}

这使用is_implies类的arg和expr方法。 documentation

在z3中存储implies（）函数的参数

1 个答案: