标签: algorithm combinations counting number-theory
给出一个数字n。如何找到所有这些不同元组的计数?
n
(i, j, k),其中(i*j)%k == 0,,1<=i<=n, 1<=j<=n, 1<=k<=n中的O(n^2)。
(i, j, k)
(i*j)%k == 0,
1<=i<=n, 1<=j<=n, 1<=k<=n
O(n^2)
答案 0 :(得分:3)
示例代码:
JobIntentService