Question

我需要重新排列等级编号，目前它们之间的间隔为1,1,2,13,20，我需要从1,2,3,4

重新排列

在我的解决方案之后，它会重新排列，但我相信必须有很多较短的版本才能重新排列。

这是我尝试过的：

if object_id('tempdb..#rank') is not null drop table #rank
if object_id('tempdb..#rank2') is not null drop table #rank2

select driver_id, zone_name, zone_rank, 0 as updated into #rank from driver_login where zone_name = 'Out of Zone' order by zone_rank 
select * into #rank2 from #rank

select * from #rank2 order by zone_rank

declare @currentRank int
declare @driverId int

while exists(select 1 from #rank2)
begin
    set @currentRank = (select min(zone_rank) from #rank2)
    set @driverId = (select driver_id from #rank2 where zone_rank = @currentRank)

    if(@currentRank != 1 and exists(select 1 from #rank where zone_rank = 1))
    begin
     declare @minRank int = (select max(zone_rank) from #rank where updated = 1)
     update #rank set zone_rank = @minRank + 1, updated = 1 where driver_id = @driverId
    end
    else if(@currentRank != 1 and not exists(select 1 from #rank where zone_rank = 1))
    begin
     update #rank set zone_Rank = 1, updated = 1 where driver_id = @driverId
    end


    delete from #rank2 where driver_id = @driverId
end

select * from #rank order by zone_rank

这是我的代码的输出：

Answer 1

在SQL Server 2008中，您可以使用ranking functions和以下语句之一：

-- Table
CREATE TABLE driver_login (
   driver_id int, 
   zone_name varchar(20), 
   zone_rank int
)
INSERT INTO driver_login
   (driver_id, zone_name, zone_rank)
VALUES
   (100, 'Out of Zone', 5),
   (113, 'Out of Zone', 10),
   (101, 'Out of Zone', 12),
   (114, 'Out of Zone', 13)

-- SELECT statement
SELECT 
   driver_id, 
   zone_name, 
   RANK() OVER (PARTITION BY zone_name ORDER BY zone_rank) zone_rank, 
   1 as updated 
INTO #rank 
FROM driver_login
WHERE zone_name = 'Out of Zone' 

SELECT *
FROM #rank

-- UPDATE statement
;WITH UpdateCTE AS (
   SELECT 
      driver_id, 
      zone_name,
      zone_rank,
      RANK() OVER (PARTITION BY zone_name ORDER BY zone_rank) AS RankID
   FROM driver_login
   WHERE zone_name = 'Out of Zone' 
) 
UPDATE UpdateCTE
SET zone_rank = RankID

SELECT *
FROM driver_login

Answer 2

尝试使用RANK函数：

返回结果集分区中每一行的排名。的   行的等级是一个加上行之前的等级数量   有问题。

ROW_NUMBER和RANK类似。 ROW_NUMBER为所有行编号   按顺序（例如1、2、3、4、5）。 RANK提供相同的   领带的数字值（例如1、2、2、4、5）。

您将看到以下内容：

WITH CTE AS
(
    SELECT driver_id,
        RANK() OVER(ORDER BY driver_id) AS RN
    FROM #rank
)
UPDATE #rank
SET zone_rank = RN
FROM #rank INNER JOIN
    CTE ON YourTable.driver_id = CTE.driver_id

Answer 3

使用可更新的CTE：

with toupdate as (
      select dl.*,
             row_number() over (order by zone_rank) as new_zone_rank
      from driver_login dl
     )
    set zone_rank = new_zone_rank,
        updated = 1
    where zone_rank <> new_zone_rank;

T-SQL重新排列1 ... n中的值

3 个答案: