Question

姓名年龄等级

雅各布10 60

约翰11 75

马特13 81

如果以上是记事本中的文本文件，我如何将其转换为以下形式的字典：

{'Jacob':{ 'Age': '10', 'Grade': 60}, 'John':{'Age': '11', 'Grade': 75}, 'Matt': {'Age': '13', 'Grade': 81}}

在python中？

Answer 1

使用正则表达式组的解决方案

import re

# Read File into variable 
file = "Name Age Grade Jacob 10 60 John 11 75 Matt 13 81"

# Match Name, age, Grade
pattern = re.compile(r'([A-z]+)\s([0-9]+)\s([0-9]+)')

# Create Dictionary Placeholder
dictionary = {}

# For each match split groups into separate vars
for name, age, grade in re.findall(pattern, file):

    # Add To Dictionary
    dictionary[name] = {
        'Age':age,
        'Grade':grade
    }

print(dictionary)

输出

{'Jacob': {'Age': '10', 'Grade': '60'}, 'John': {'Age': '11', 'Grade': '75'}, 'Matt': {'Age': '13', 'Grade': '81'}}

将文本读入变量

file = open('textdocument.txt', 'r').read()

Answer 2

您可能缺少的部分是基于空格的行分割。

data = {}
with open('textfile') as fh:
    for line in fh:
        name, age, grade = line.split()
        data[name] = { 'age': age, 'grade': grade}

如何在python中将多列表转换为字典

2 个答案: