以前,我创建了一个SELECT来计算营业日(周末/节假日),但对于每个记录在特定日期范围内均无效。建议我使用日历表,该日历表实际上可以满足我所保留的其他要求,但是我不知道如何在工作日计算INI
和END
。
我试图用半左联接和联接(也建议)进行SELECT,但似乎根本无法计算。
这是日历表:
CalendarId DateValue DayNumberOfWeek NameOfDay NameOfMonth WeekOfYear JulianDay USAIsBankHoliday USADayName
----------- ----------------------- --------------- ---------- ----------- ----------- ----------- ---------------- -------------------
20100101 2010-01-01 00:00:00.000 5 Viernes Enero 1 1 1 Año nuevo
我的桌子:
INI FIN DD --DATEDIFF BETWEEN DATES
------------------------------ ------------------------------ -----------
20180129 20180211 14
我尝试计算营业日
SELECT CONVERT(NVARCHAR,INI,112) AS INI,
CONVERT(NVARCHAR,FIN,112) AS FIN,
DATEDIFF(DD, INI, FIN)+1 AS DD
FROM HISTORICOLICMED T
WHERE EXISTS(
SELECT 1 FROM CALENDAR C
WHERE T.INI = C.CALENDARID and T.FIN = C.CALENDARID
AND C.USAISBANKHOLIDAY = 0 BETWEEN T.INI AND T.FIN)
我希望得到正确的工作日计算,包括假期,因此对于上面的示例,我将得到类似的信息:
INI FIN DD ND
------------------------------ ------------------------------ ----- -----
20180129 20180211 14 10
答案 0 :(得分:1)
从子菜单中选择日历表中INI
和FIN
之间的行数,即工作日。
SELECT CONVERT(NVARCHAR,INI,112) AS INI,
CONVERT(NVARCHAR,FIN,112) AS FIN,
DATEDIFF(DD, INI, FIN)+1 AS DD,
(SELECT COUNT(*) FROM CalendarTable WHERE ...) AS ND
FROM HISTORICOLICMED
答案 1 :(得分:1)
建议的解决方案:
set datefirst 1;
select INI
,FIN
, DATEDIFF(DD, INI, FIN)+1 as DD
,(DATEDIFF(DD, INI, FIN)+1)
-(DATEDIFF(WK, INI, FIN)*2)
-(case DATEPART(DW, INI) when 7 then 1 else 0 end)
-(case DATEPART(DW, FIN) when 6 then 1 else 0 end)
-(select COUNT(*) from CALENDAR
where DateValue between INI and FIN
and USAIsBankHoliday = 1)
as ND -- Working days except US Bank holidays
from HISTORICOLICMED;