Question

我基于this solution在sql上创建了类似于NETWORKDAYS的函数，它可以正确返回工作日，而记录（BEG和END）在工作日。

BEG        END         businessd
--------------------------------
01/01/2018 15/01/2018  10       

--(15 days total)-(1st jan)-(4 weekends) = 10 | correct result

但是在某些情况下，周末会“存储” BEG或END，这会增加几天的时间：

BEG        END         businessd
--------------------------------
01/01/2018 28/01/2018  20       

--(28 days total)-(1st jan)-(4 weekends) = 19 | incorrect result

我的代码在datediff和BEG之间进行了FIN运算，并减去了存储在holydays表中的周末和节假日

    SELECT e.*, 
            DATEDIFF(DAY, cast(BEG as datetime), cast(FIN as datetime))+1 --sum end date day
              -(SELECT
               (DATEDIFF(WK, cast(BEG as datetime), cast(FIN as datetime)) )
              +(CASE WHEN DATENAME(dw, cast(BEG as datetime)) = 'Sunday' THEN 1 ELSE 0 END)
              +(CASE WHEN DATENAME(dw, cast(FIN as datetime)) = 'Saturday' THEN 1 ELSE 0 END)
            ) * 2
            -(SELECT COUNT(*) FROM holydays nl
             WHERE nl.FECHA BETWEEN cast(BEG as datetime) AND cast(FIN as datetime)
            ) AS businessd,

            convert(nvarchar(6),cast(BEG as datetime),112) as iddate --new id based on fin
    FROM e
    ORDER BY original_ini,BEG

如何处理这些案件以正确计算工作日？

Answer 1

您可以为此使用日历表。这样操作将非常容易。

您甚至可以处理银行假期

Check This和this (Calendar Table)

select * from calendar where isWorkDay = 1

将为您提供工作日，然后可以进行简单的加入，例如

select * from t
where exists 
( select 1 from calendar where isWorkDay = 1 and calendar.dt betweenn t.beg and t.end)

模拟NETWORKDAYS返回错误的工作日

1 个答案: