计算五分位数

Question

我正在尝试计算数据集（0和5）的五分位数范围，并将其用作我的计算基础（我从网站上粘贴了以下查询） http://www.sqlservercentral.com/articles/PERCENT_RANK/141532/

WITH C AS
(
   SELECT
      SalesPersonID,
      SaleYear, SaleAmt,
      rk = RANK() OVER (ORDER BY SaleAmt),
      nr = COUNT(*) OVER ()
   FROM ##Sales
)
SELECT
    SalesPersonID,
    SaleYear,
    SaleAmt,
    PercentileRank = 1.0*(rk-1)/(nr-1)
FROM C;

我需要修改什么才能使其达到五分之一范围？

Answer 1

WITH C AS
(
   SELECT
      SalesPersonID,
      SaleYear, SaleAmt,
      rk = RANK() OVER (ORDER BY SaleAmt),
      nr = COUNT(*) OVER ()
   FROM ##Sales
)
SELECT
    SalesPersonID,
    SaleYear,
    SaleAmt,
    PercentileRank = 1.0*(rk-1)/(nr-1),
    Quintile=(rk-1)/(nr/5)+1
FROM C;