Question

如何对结果1中的值进行求和，如结果2

Result 1
    SalesRep    Customer    Product Quantity    Total
    Doe, John   AA Corp     P1      50          5000
    Doe, John   CA Corp     P2      67          6030
    Doe, John   EA Corp     P3      46          5980
    Doe, John   GA Corp     P2      22          1980
    Doe, John   HA Corp     P3      43          5590
    Doe, John   IA Corp     P1      35          3500 | Sum this two 
    Doe, John   IA Corp     P2      24          2160 | make second record 0
    Doe, John   JA Corp     P2      66          5940
    Doe, John   MA Corp     P4      59          7670 
    Doe, John   OA Corp     P2      43          3870 | Sum this two 
    Doe, John   OA Corp     P4      14          1820 | make second record 0
    Doe, John   PA Corp     P1      89          8900


Result 2
    SalesRep    Customer    Product Quantity    TotalPrice
    Doe, John   AA Corp     P1      50          5000
    Doe, John   CA Corp     P2      67          6030
    Doe, John   EA Corp     P3      46          5980
    Doe, John   GA Corp     P2      22          1980
    Doe, John   HA Corp     P3      43          5590
    Doe, John   IA Corp     P1      59          5660
    Doe, John   IA Corp     P2      0           0
    Doe, John   JA Corp     P2      66          5940
    Doe, John   MA Corp     P4      59          7670
    Doe, John   OA Corp     P2      57          5690
    Doe, John   OA Corp     P4      0           0
    Doe, John   PA Corp     P1      89          8900

Answer 1

有一种可能性，虽然我真的没有看到商业案例。我想这只是一个技术问题：

SELECT 
  T.SalesRep, T.Customer, T.Product,
  CASE WHEN EXISTS (SELECT 1 FROM MyTable AS T1
                    WHERE T1.SalesRep = T.SalesRep
                    AND T1.Customer = T.Customer
                    AND T1.Product < T.Product)
       THEN 0
       ELSE SUM(T.Quantity) OVER (PARTITION BY T.SalesRep, T.Customer)
  END AS Quantity,
  CASE WHEN EXISTS (SELECT 1 FROM MyTable AS T1
                    WHERE T1.SalesRep = T.SalesRep
                    AND T1.Customer = T.Customer
                    AND T1.Product < T.Product)
       THEN 0
       ELSE SUM(T.Total) OVER (PARTITION BY T.SalesRep, T.Customer)
  END AS Total
FROM MyTable AS T

对于两个CASE条款，他们读到：“当同一销售代表和客户的产品记录较少时（这是我的假设？），则将值设为零。否则，总结一下按销售代表和客户分组的所有值。每个销售代表和客户也可以使用两种以上（不同的！）产品。

注意：如果每个销售代表可以有几个相同的产品。和客户一样，这不起作用，你必须比较两个嵌套选择中的其他一些值（例如T1.ID < T.ID）

请注意：这可能是错误的，因为我必须对您的要求做出一些假设。

Answer 2

好吧，如果您 reeeeeeally 需要带有零的行，那么您可以这样做：

select salesrep,customer,min(product),sum(quantity) as quantity,sum(price) as totalprice
from results1
group by salesrep,customer
union
select salesrep,customer,max(product),0 as quantity,0 as totalprice
from results1
group by salesrep,customer
having count(1)>1;

技术上没有考虑如果有两个以上(salesrep,customer,product)三元组会发生什么，但只要MS-SQL具有generate_series()和{{的等价物，就可以修复1}} PostgreSQL的功能。

计算小计

2 个答案: