Question

heloo我目前在ALTERA DE2开发板上工作。我要使用液晶显示屏。我强迫打开它。在此代码中，如果编号为1的代码为：“ 0100110001”，则lcd_bus是excdle的lcd的输出。所以如果我写代码：当1 => lcd_bus <=“ 0100110001”时，我将看到输出lcd_bus = 0100110001。这是此示例的代码：

LIBRARY ieee;
 USE ieee.std_logic_1164.ALL;
 USE IEEE.STD_LOGIC_ARITH.ALL;
 USE IEEE.STD_LOGIC_UNSIGNED.ALL;

 ENTITY lcd_user_logic IS


                        GENERIC (display_resolution : INTEGER :=23;   -- counter to get to the lowest ferquncy 
                                    display_counter: INTEGER :=8);      -- counter to get to 97KHz ferquincy 

 PORT(




        lcd_bus_ones : IN STD_LOGIC_VECTOR(9 DOWNTO 0);









 --COUNTER_VECTOR :IN  STD_LOGIC_VECTOR(display_counter downto 0);
 lcd_busy : IN STD_LOGIC; --lcd controller busy/idle feedback
 clk : IN STD_LOGIC; --system clock
 lcd_clk : OUT STD_LOGIC;
 reset_n : OUT STD_LOGIC;
 lcd_enable : buffer STD_LOGIC; --lcd enable received from lcd controller
 lcd_bus : BUFFER STD_LOGIC_VECTOR(9 DOWNTO 0)); --data andcontrol signals
 --The MSB is the rs signal, followed by the rw signal.
 -- The other 8 bits are the data bits.
 END lcd_user_logic;

 ARCHITECTURE behavior OF lcd_user_logic IS


signal lcd_bus_ones_signal :  STD_LOGIC_VECTOR(display_counter+1 downto 0);



 BEGIN

 lcd_bus_ones_signal<=lcd_bus_ones;












 PROCESS(clk,lcd_bus_ones,lcd_bus_ones_signal)
 VARIABLE char : INTEGER RANGE 0 TO 12 := 0;
        BEGIN

                IF(clk'EVENT AND clk = '1') THEN

                    IF(lcd_busy = '0' AND lcd_enable = '0') THEN
                    --  lcd_bus <=  lcd_bus_ones;   
                            lcd_enable <= '1';
                                IF(char < 12) THEN
                                        char := char + 1;
                END IF;
 CASE char IS



                    ---------------------------------------------------------------------------this is the test 

                  WHEN 1 => lcd_bus <="1000110001";






 WHEN OTHERS => lcd_enable <= '0';
 END CASE;
 ELSE
 lcd_enable <= '0';
 END IF;
 END IF;
 END PROCESS;







 reset_n <= '1';
 lcd_clk <= clk;



 END behavior;

，输出实际上将是lcd_bus <=“ 1000110001” enter image description here

如果例如我想为lcd_bus输入一个值，lcd_bus <= lcd_bus_ones，那么我会得到lcd_bus =“ 0000000000” 代码看起来像这样：

LIBRARY ieee;
 USE ieee.std_logic_1164.ALL;
 USE IEEE.STD_LOGIC_ARITH.ALL;
 USE IEEE.STD_LOGIC_UNSIGNED.ALL;

 ENTITY lcd_user_logic IS


                        GENERIC (display_resolution : INTEGER :=23;   -- counter to get to the lowest ferquncy 
                                    display_counter: INTEGER :=8);      -- counter to get to 97KHz ferquincy 

 PORT(




        lcd_bus_ones : IN STD_LOGIC_VECTOR(9 DOWNTO 0);









 --COUNTER_VECTOR :IN  STD_LOGIC_VECTOR(display_counter downto 0);
 lcd_busy : IN STD_LOGIC; --lcd controller busy/idle feedback
 clk : IN STD_LOGIC; --system clock
 lcd_clk : OUT STD_LOGIC;
 reset_n : OUT STD_LOGIC;
 lcd_enable : buffer STD_LOGIC; --lcd enable received from lcd controller
 lcd_bus : BUFFER STD_LOGIC_VECTOR(9 DOWNTO 0)); --data andcontrol signals
 --The MSB is the rs signal, followed by the rw signal.
 -- The other 8 bits are the data bits.
 END lcd_user_logic;

 ARCHITECTURE behavior OF lcd_user_logic IS


signal lcd_bus_ones_signal :  STD_LOGIC_VECTOR(display_counter+1 downto 0);



 BEGIN

 lcd_bus_ones_signal<=lcd_bus_ones;












 PROCESS(clk,lcd_bus_ones,lcd_bus_ones_signal)
 VARIABLE char : INTEGER RANGE 0 TO 12 := 0;
        BEGIN

                IF(clk'EVENT AND clk = '1') THEN

                    IF(lcd_busy = '0' AND lcd_enable = '0') THEN
                    --  lcd_bus <=  lcd_bus_ones;   
                            lcd_enable <= '1';
                                IF(char < 12) THEN
                                        char := char + 1;
                END IF;
 CASE char IS



                    ---------------------------------------------------------------------------this is the test 

                  WHEN 1 => lcd_bus <=lcd_bus_ones;






 WHEN OTHERS => lcd_enable <= '0';
 END CASE;
 ELSE
 lcd_enable <= '0';
 END IF;
 END IF;
 END PROCESS;







 reset_n <= '1';
 lcd_clk <= clk;



 END behavior;

所以输出结果应该是这样

enter image description here

问题出在这个陈述上：
IF（lcd_busy ='0'并且lcd_enable ='0'）然后

有人知道如何解决此问题吗？

Answer 1

对不起，信誉不足，无法发表评论。

仅通过波形显示中显示的2或3个信号就很难确定发生了什么。请至少将lcd_busy和lcd_enable添加到波形中。看来您的lcd_busy信号可能设置为非0的值。我已经模拟了代码，对lcd_bus_ones信号的分配对我来说很好。

此外，如果可能的话，很高兴看到该实体外部发生了什么事情。

您要char停在12点吗？除非您提供一种重置char的方法，否则现在定义的方式将达到12，并且有问题的分配不会再发生。

VHDL控制LCD屏幕ALTERA DE 2

1 个答案: