答案 0 :(得分:0)
看下面的Java代码以了解解决方案
/* A Naive Java Program for LIS Implementation */
class LIS
{
static int max_ref; // stores the LIS
/* To make use of recursive calls, this function must return
two things:
1) Length of LIS ending with element arr[n-1]. We use
max_ending_here for this purpose
2) Overall maximum as the LIS may end with an element
before arr[n-1] max_ref is used this purpose.
The value of LIS of full array of size n is stored in
*max_ref which is our final result */
static int _lis(int arr[], int n)
{
// base case
if (n == 1)
return 1;
// 'max_ending_here' is length of LIS ending with arr[n-1]
int res, max_ending_here = 1;
/* Recursively get all LIS ending with arr[0], arr[1] ...
arr[n-2]. If arr[i-1] is smaller than arr[n-1], and
max ending with arr[n-1] needs to be updated, then
update it */
for (int i = 1; i < n; i++)
{
res = _lis(arr, i);
if (arr[i-1] < arr[n-1] && res + 1 > max_ending_here)
max_ending_here = res + 1;
}
// Compare max_ending_here with the overall max. And
// update the overall max if needed
if (max_ref < max_ending_here)
max_ref = max_ending_here;
// Return length of LIS ending with arr[n-1]
return max_ending_here;
}
// The wrapper function for _lis()
static int lis(int arr[], int n)
{
// The max variable holds the result
max_ref = 1;
// The function _lis() stores its result in max
_lis( arr, n);
// returns max
return max_ref;
}
// driver program to test above functions
public static void main(String args[])
{
int arr[] = { 10, 22, 9, 33, 21, 50, 41, 60 };
int n = arr.length;
System.out.println("Length of lis is "
+ lis(arr, n) + "n");
}
}