Question

我正在尝试使用Javascript制作保龄球模拟器。我创建了一个函数，它在0和0之间取一个随机数。 10.在保龄球比赛中，你每轮可以投2次。我设法得到2个值，如5和8，但问题是你不能在保龄球投掷超过10针。当我扔6时，我无法弄清楚如何得到值4,3,2,1或0。

这是我在代码段中的代码......

		var team1 = ["Jason", "Jake", "Jane", "Joe"];
        var team2 = ["John", "Drake", "Nick", "Joseph"];

		var rounds = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
		var pin = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

		for (var team1 = 0; team1 < 2; team1++) {
			console.log(getRandomPin(team1));
		}

		for (var team2 = 0; team2 < 2; team2++) {
			console.log(getRandomPin(team2));
		}

		function getRandomPin(min, max) {
		    min = Math.ceil(0);
		    max = Math.floor(11);
		    return Math.floor(Math.random() * (11 - 0)) + 0;
		}

提前谢谢。

Answer 1

这里有一种方法可以跟踪留下多少针脚以及有多少针脚......这里我只使用了一个＆＃39;团队＆＃39;，但你可以很容易地做到两个或更多团队。请看一下，看看这对你有帮助。

＆＃13;

    var team1 = ["Jason", "Jake", "Jane", "Joe"];
    var team2 = ["John", "Drake", "Nick", "Joseph"];

    var rounds = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
    var pin = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

    var aux2 = 0;
    var maxVal = 11;
    for (var team2 = 0; team2 < 2; team2++) {
       maxVal = maxVal - aux2;
       console.log('Pins Remaining: ' + (maxVal-1));
       var pins = getRandomPin(0, maxVal);
       aux2 += pins;
       if (pins == 10){
          console.log('Round-' + (team2 + 1) +' | STRIKE!');
          break; //leaves the function because when strike occurs no second round is played
       }else{       
          console.log('Round-' + (team2 + 1) +' | pins striked: ' + pins);
       }
    }    
    console.log('Total pins striked: ' + aux2);
    aux2 = 0;
    maxVal = 11;    
    
    function getRandomPin(min, max) {
        return Math.floor(Math.random() * (max - min)) + min;
    }

＆＃13;

Answer 2

您需要一个变量来跟踪剩余的针数。不要忘记在轮次之间重置它。

var team1 = ["Jason", "Jake", "Jane", "Joe"];
var team2 = ["John", "Drake", "Nick", "Joseph"];

var rounds = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

var pins = 11;
for (var team1 = 0; team1 < 2; team1++) {
    console.log('Adam', getRandomPin());
}

pins = 11;
for (var team2 = 0; team2 < 2; team2++) {
    console.log('Tom', getRandomPin());
}

function getRandomPin() {
    var pinsKnocked = Math.floor(Math.random() * pins);
    pins -= pinsKnocked;
    return pinsKnocked;
}

Answer 3

我的代码有点冗长，但我尝试添加注释来解释我在编写时所思考的一切。它仍然可以进一步优化，但我希望这会让你以一种稍微不同的方式思考这个问题。我接下来要做的一个这样的优化是将重复代码（两个相似的循环）移动到单个函数中。另一个优化是添加if语句以跳过第二次投掷，如果第一次投掷获得10个引脚。无论如何，你走了：

var team1 = ["Adam", "Ayman", "Matthijs", "Joey"];
var team2 = ["Tom", "Afzal", "Jef", "Anouar"];
var rounds = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

// Let's loop over all the rounds
for (var roundNumber = 1; roundNumber <= rounds.length; roundNumber++) {
    // This will tell us what round we are on
    console.log('******Round Number:', roundNumber);
    // Let's let team number 1 go first
    console.log('***Team One');
    for (var i = 0; i < team1.length; i++) {
        // There are always 10 pins standing in the beginning
        var standingPins = 10;
        // The we see how many pins are hit first
        var pinsHitFirst = getRandomPin(standingPins);
        // The number of pins left standing
        standingPins = standingPins - pinsHitFirst;
        // and the number of pins the player hit the second attempt
        var pinsHitSecond = getRandomPin(standingPins);
        console.log(team1[i] + '\'s Score: ', pinsHitFirst, pinsHitSecond);
    }    // Now it's time for team number 2
    console.log('***Team Two');
    for (var i = 0; i < team2.length; i++) {
        // There are always 10 pins standing in the beginning
        var standingPins = 10;
        // The we see how many pins are hit first
        var pinsHitFirst = getRandomPin(standingPins);
        // The number of pins left standing
        standingPins = standingPins - pinsHitFirst;
        // and the number of pins the player hit the second attempt
        var pinsHitSecond = getRandomPin(standingPins);
        console.log(team2[i] + '\'s Score: ', pinsHitFirst, pinsHitSecond);
    }
}

// This will allow us to randomly select the number of pins hit
// based on how many pins were still standing
function getRandomPin(remainingPins) {
    return Math.round(Math.random() * remainingPins);
}

Javascript - 保龄球游戏模拟器

3 个答案: