Question

我需要为一场保龄球比赛写一个程序。要求用户输入游戏数量和投球手数量。对于每个投球手，获得每场比赛的得分。显示分数。计算每个投球手的平均值并显示平均值。最后显示团队平均值。我写了一个代码，它没有错误，但问题是它不计算玩家的平均分数和团队的总分。需要这些计算的帮助。

#include <stdio.h>

int main()
{
    int playerTotal = 0;
    int teamTotal = 0;
    int score;
    int numgames, player, bowler, game;

    printf ("How many games?\n");
    scanf ("%d", &numgames);
    printf ("How many players?\n");
    scanf ("%d", &player);

    for (bowler = 1; bowler <= 3; bowler++)
       {
        for (game = 1; game <= 2; game++)
           {
        printf ("\nEnter the score for game %d for bowler %d: ", game, bowler);
        scanf ("%d", &score);

        playerTotal += score;
           }
        printf ("\nThe average for bowler %d is: ", bowler, playerTotal/2);

        printf ("\nThe total for the game is:", teamTotal);

        teamTotal += playerTotal;
       }


   return 0;
}

Answer 1

这与“不计算”无关 - 你只是不打印它们。这样：

printf ("\nThe average for bowler %d is: ", bowler, playerTotal/2);
printf ("\nThe total for the game is:", teamTotal);

应该是：

printf ("\nThe average for bowler %d is: %.1f", bowler, playerTotal / 2.0);
printf ("\nThe running team total is: %d", teamTotal);

请注意从2到2.0的更改，因为playerTotal是int，但如果总数是奇数，则平均值将（或应该）具有.5最后{1}}。

您还希望在外部playerTotal = 0;循环开始时设置for，否则每位玩家将获得之前输入分数的所有投球手的分数，评分系统可能不是那么公平。你应该改变：

for (bowler = 1; bowler <= 3; bowler++)
       {
        for (game = 1; game <= 2; game++)
           {

为：

for (bowler = 1; bowler <= player; ++bowler) {
    playerTotal = 0;

    for (game = 1; game <= numgames; ++game) {

也会循环播放用户输入的次数。如果你这样做，你还需要改变：

printf ("\nThe average for bowler %d is: %.1f", bowler, playerTotal / 2.0);

为：

printf ("\nThe average for bowler %d is: %.1f", bowler,
            playerTotal / (double) numgames);

将您的平均值除以正确的游戏数量。

除了那些事情，你做了一个非常好的尝试。

保龄球比赛的C程序

1 个答案: