Question

我们在DataSource下方，我们有以下脚本。

robin    = graph.addVertex(label,'person','name','robin');
jeff     = graph.addVertex(label,'person','name','jeff');
andrew   = graph.addVertex(label,'person','name','andrew');

robin.addEdge('Communication',jeff,'date','2017-12-11T00:00:00Z','weight',1);
robin.addEdge('Communication',jeff,'date','2017-12-10T00:00:00Z','weight',1);
robin.addEdge('Communication',jeff,'date','2017-12-09T00:00:00Z','weight',1);
robin.addEdge('Communication',andrew,'date','2017-12-11T00:00:00Z','weight',1);
robin.addEdge('Communication',andrew,'date','2017-12-10T00:00:00Z','weight',1);
robin.addEdge('Communication',andrew,'date','2017-12-09T00:00:00Z','weight',1);

jeff.addEdge('Communication',robin,'date','2017-12-11T00:00:00Z','weight',1);
jeff.addEdge('Communication',robin,'date','2017-12-10T00:00:00Z','weight',1);
jeff.addEdge('Communication',robin,'date','2017-12-09T00:00:00Z','weight',1);
jeff.addEdge('Communication',andrew,'date','2017-12-11T00:00:00Z','weight',1);
jeff.addEdge('Communication',andrew,'date','2017-12-10T00:00:00Z','weight',1);
jeff.addEdge('Communication',andrew,'date','2017-12-09T00:00:00Z','weight',1);
andrew.addEdge('Communication',robin,'date','2017-12-11T00:00:00Z','weight',1);
andrew.addEdge('Communication',robin,'date','2017-12-10T00:00:00Z','weight',1);
andrew.addEdge('Communication',robin,'date','2017-12-09T00:00:00Z','weight',1);
andrew.addEdge('Communication',jeff,'date','2017-12-11T00:00:00Z','weight',1);
andrew.addEdge('Communication',jeff,'date','2017-12-10T00:00:00Z','weight',1);
andrew.addEdge('Communication',jeff,'date','2017-12-09T00:00:00Z','weight',1);

我们运行下面的脚本。

g.V().has('name','robin').as('v').
  repeat(outE().as('e').otherV().as('v').simplePath()).
    until(has('name','jeff')).
  store('a').
    by('name').
  store('a').
    by(select(all, 'v').unfold().values('name').fold()).
  store('a').
    by(select(all, 'e').unfold().
       store('x').
         by(union(values('weight'),
                  select('x').count(local)).fold()).
       cap('x').
       store('a').
         by(unfold().limit(local, 1).fold()).unfold().
       sack(assign).
         by(constant(1d)).
       sack(div).
         by(union(constant(1d),
                  tail(local, 1)).sum()).
       sack(mult).
         by(limit(local, 1)).
       sack().sum()).
  cap('a')

得到了结果： ==＆GT; [杰夫，杰夫，杰夫，杰夫，杰夫，杰夫，杰夫，杰夫，杰夫，杰夫，杰夫，杰夫，[循环赛，杰夫]，[循环赛，杰夫]，[循环赛，杰夫]，[1] 1.0，[1,1]，1.5％，[1,1,1]，1.8333333333333333，[循环赛，安德鲁，杰夫]，[循环赛，安德鲁，杰夫]，[循环赛，安德鲁，杰夫]，[循环赛，安德鲁，杰夫]，[循环赛，安德鲁，杰夫]，[循环赛，安德鲁，杰夫]，[循环赛，安德鲁，杰夫]，[循环赛，安德鲁，杰夫]，[循环赛，安德鲁，杰夫]，[1,1,1， 1,1]，2.283333333333333，[1,1,1,1,1,1,1]，2.5928571428571425，[1,1,1,1,1,1,1,1,1]，2.8289682539682537，[1， 1,1,1,1,1,1,1,1,1,1] 3.0198773448773446，[1,1,1,1,1,1,1,1,1,1,1,1,1] ，3.180133755133755，[1,1,1,1,1,1,1,1,1,1,1,1,1,1,1] 3.3182289932289937，[1,1,1,1,1,1， 1,1,1,1,1,1,1,1,1,1,1] 3.439552522640758，[1,1,1,1,1,1,1,1,1,1,1,1， 1,1,1,1,1,1,1]，3.547739657143682，[1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1， 1,1,1,1,1]，3.6453587047627294]

但我们希望按相同路径分组，并将相同路径的分数相加。有什么建议吗？现在的脚本我们有相同的路径，如[robin，andrew，jeff]，但它们是分开的。

结果我们想得到如下结果： [[循环赛，杰夫] = 4.3333333333333333，[循环赛，安德鲁，杰夫] = 27.85604971]

计算路径问题的权重

0 个答案: