我正在运行此代码
module neuron_xor(x0, x1, y4);
input signed [4:0] x0, x1;
reg signed [4:0] w02, w03, w12, w13, w24, w34;
reg signed [4:0] th2, th3, th4;
wire signed [4:0] y2, y3;
output signed [4:0] y4;
neuron n2(x0, x1, w02, w12, th2, y2);
neuron n3(x0, x1, w03, w13, th3, y3);
neuron n4(y2, y3, w24, w34, th4, y4);
initial begin
w02 = 2; w03 = -2;
w12 = 2; w13 = -2;
w24 = 2; w34 = 2;
th2 = 1; th3 = -3; th4 = 3;
end
endmodule
使用此测试平台:
`timescale 1ns/100ps
module tb_neuron_xor();
reg signed [4:0] x0, x1;
reg signed [4:0] w02, w03, w12, w13, w24, w34;
reg signed [4:0] th2, th3, th4;
wire signed [4:0] y2, y3;
wire signed [4:0] y4;
reg signed [4:0] ctrl;
integer i, j, flag;
neuron n2(x0, x1, w02, w12, th2, y2);
neuron n3(x0, x1, w03, w13, th3, y3);
neuron n4(y2, y3, w24, w34, th4, y4);
initial begin
$dumpfile("tb_neu_xor.vcd");
$dumpvars;
flag = 0;
#10;
for (i = -16; i < 15; i = i + 1) begin
for (j = -16; j < 15; j = j + 1) begin
x0 = i; x1 = j;
ctrl = x0 ^ x1;
if (ctrl != y4) begin
flag = 1;
$display("Error: x0=%b, x1=%b, y4=%b, ctrl=%b", x0,x1,y4,ctrl);
end
$display("y4=%d, ctrl=%d", y4, ctrl);
end
end
if (flag == 0) begin
$display("No Error!");
end
#10;
$finish;
end
endmodule
每次迭代都得到y4 = X.据我所知,这种情况发生了,因为没有给y4初始值,默认值是X.但是,我不能将y4的类型更改为reg以便为其赋值。这将导致在测试台,第15行,神经元n4:
中出现错误消息tb_neuron_xor.v:15:错误:reg y4;不能由原语或连续分配驱动。 tb_neuron_xor.v:15:错误:输出端口表达式必须支持连续分配。 tb_neuron_xor.v:15::神经元的端口y0连接到y4
我怎样才能解决这个问题呢?
如果需要更好的上下文,下面是神经元模块的定义方式:
module neuron(x0, x1, w0, w1, th0, y0);
input signed [4:0] x0, x1;
input signed [4:0] w0, w1;
input signed [4:0] th0;
output reg signed [4:0] y0;
reg signed [11:0] a0, a1, a2;
always @(x0 or x1 or w0 or w1 or th0)
begin
a0 = x0*w0;
a1 = x1*w1;
a2 = a0 + a1;
if (a2 >= th0)
y0 = 1;
else
y0 = 0;
end
endmodule
答案 0 :(得分:1)
为什么不将默认值分配给y0
的{{1}}?
neuron()
我还建议您在注册表中使用重置,并在模拟开始时重置它们。