最长公共子词不正确的结果

时间:2017-11-01 10:02:44

标签: c++ algorithm dynamic-programming

我一直试图编写一个程序,计算两个字符串共有的最长公共连续序列(或子字)。代码工作没有任何语法错误,但每次我得到像237743等乱码随机结果,希望有人可以弄清楚我哪里出错了。 例如, 如果我输入第一个单词作为' stack'第二个词是' stackoverflow' ,它应该输出5(常用字=堆栈,长度5),但它给了我' 2752053'

#include <iostream>

using namespace std;

int getlcw(char arr1[],char arr2[])
{
    u=sizeof(arr1)/sizeof(arr1[0]);
    v=sizeof(arr2)/sizeof(arr2[0]);
    if(u==0||v==0)
    {   cout<<"fail";
        return 0;
    }
    int lcw[u+1][v+1]; \\1 extra row and column to indicate word has ended , no chance for subword
    int maxlcw=0;
    for(int i=0;i<u+1;++i) \\intialise last row and col to 0
    {
        lcw[i][v+1]=0;
    }
    for(int i=0;i<v+1;++i)
    {
        lcw[u+1][i]=0;
    }
    for(int i=u;i>=0;--i)
    {
        for(int j=v;j>=0;--j)
        {
            if(arr1[j]==arr2[i])
                lcw[i][j]=1+(lcw[i+1][j+1]);
            else
                lcw[i][j]=0;
            if(lcw[i][j]>maxlcw)
                maxlcw=lcw[i][j];
        }
    }
    return maxlcw;
    }

int main()
{   int x,y;
    cout<<"enter size of word 1\n";
    cin>>x;
    char arr1[x];
    cout<<"enter size of word 2\n";
    cin>>y;
    char arr2[y];
    cout<<"word 1\n";
    for(int i=0;i<x;++i)
    {
        cin>>arr1[i];
    }
    cout<<"word 2\n";
    for(int j=0;j<y;++j)
    {
        cin>>arr2[j];
    }
    int ans=getlcw(arr1,arr2);
    cout<<ans;
    cin>>x;

}

这是我从算法中获得想法的链接 -

https://www.iarcs.org.in/inoi/online-study-material/topics/dp-classics.php

1 个答案:

答案 0 :(得分:0)

您可以通过两种方式解决它:查看它:

自上而下的方法:

int getlcw(char arr1[],char arr2[])
{
    u=sizeof(arr1)/sizeof(arr1[0]);
    v=sizeof(arr2)/sizeof(arr2[0]);
    if(u==0||v==0)
    {   cout<<"fail";
        return 0;
    }
    int lcsw[u+1][v+1]; \\1 extra row and column to indicate word has ended , no chance for subword
    int maxlcw=0;


    for(int i=0; i<u+1;i++)
    {
        for(j=0; j<v+1; j++)
        {
            if(i == j)              lcsw[i][j] = 0;
            if(arr1[i]!= arr2[j])   lcsw[i][j] = 0;
            else                    
            {
                                    lcsw[i][j] = 1+lcsw[i-1][j-1];
                                    maxlcw= max(maxlcw, lcsw[i][j]);
            }
        }
    }

    return maxlcw;
}

自下而上当你正在尝试:

int getlcw(char arr1[],char arr2[])
{
    u=sizeof(arr1)/sizeof(arr1[0]);
    v=sizeof(arr2)/sizeof(arr2[0]);
    if(u==0||v==0)
    {   cout<<"fail";
        return 0;
    }
    int lcsw[u+1][v+1]; \\1 extra row and column to indicate word has ended , no chance for subword
    int maxlcw=0;

    for(int i=u;i>=0;i--)
    {
        for(int j=v;j>=0;j--)
        {
            if(i == j)              lcsw[i][j] = 0;
            if(arr1[i]!= arr2[j])   lcsw[i][j] = 0;
            else                    
            {
                                    lcsw[i][j] = 1+lcsw[i+1][j+1];
                                    maxlcw= max(maxlcw, lcsw[i][j]);
            }
        }
    }
}