我需要创建一个程序,要求输入最少量的硬币以获得随机数量。我遇到了一个问题,实际上要求最低金额而不破坏程序。我也有这个系列的程序:
print (x, "cents requires", val[0], "coins:", val[1])
仅显示99美分的结果。我不确定我需要改变什么来修复它。我觉得问题就在于:
if total == amount:
我尝试过使用
if total == amount and amount == #(I've tried multiple different variables here.)
# imports
import random
# program welcome
print("The purpose of this exercise is to enter the least number of coin values")
print("that add up to a displayed target value. \n")
print("Enter coins values as 1-penny, 5-nickel, 10-dime, and 25- quarter.")
print("Hit return after the last entered coin value.")
print("-------------------")
# init
terminate = False
empty_str = ""
# start game
while not terminate:
amount = random.randint(1,99)
print("Enter coins that add up to", amount, "cents, one per line.\n")
game_over = False
total = 0
while not game_over:
valid_entry = False
coins = [1, 5, 10, 25]
d = {}
# finds the minimum # of coins needed to
def m(cents):
if cents in d.keys():
return d[cents]
elif cents > 0:
choices = [(m(cents - x)[0] + 1, m(cents - x)[1] + [x]) for x in coins if cents >= x]
d[cents] = min(choices)
return d[cents]
else:
d[0] = (0, [])
return d[0]
for x in range(1, 100):
val = m(x)
while not valid_entry:
if total == 0:
entry = input("Enter first coin: ")
else:
entry = input("Enter next coin: ")
if entry in (empty_str, "1", "5", "10", "25"):
valid_entry = True
else:
print ("Invalid entry")
if entry == empty_str:
if total == amount:
print("Correct!")
game_over = True
if game_over:
entry = input("\nWould you like to play again (y/n)?: ")
if entry == "n":
terminate = True
else:
print("Sorry - you only entered", total, "cents")
print (x, "cents requires", val[0], "coins:", val[1])
game_over = True
else:
total = total + int(entry)
if total > amount:
print("Sorry - total amount exceeds", amount, "cents.")
game_over = True
if game_over:
entry = input("\nTry again (y/n)?: ")
if entry == "n":
terminate = True
print("Thanks for playing! Goodbye!")`