Question

我有一个我必须阅读和解析的文本文件。每行包含ASCII格式的HEX值。例如：

转换为带符号的32位整数后，我必须按以下方式检查位：

bit #31 => should result in decimal 0 or 1
bit #30 to 23 => should result in decimal 0 to 10
bit #22 to 0 => should result in a signed decimal number

我将原始int32分配给以下struct / union（我只设置了raw部分）：

typedef struct DATA{
    union {
        int32_t raw;
        struct {
            int32_t data:24;
            uint8_t operation:7;
            uint8_t binop:1;
        };
    } members;
} data_t;

现在的问题是，在Linux机器上并使用GCC进行编译（我试过4.8和5.4）我使用以下函数得到了正确的结果：

void vm_data_debug(data_t* const inst, int const num) {
    printf("DEBUG DATA #%d => "
                   " RAW: %-12d"
                   " BINCODE: %-1d"
                   "\tOPCODE: %-1d"
                   "\tDATA: %-10d", num, inst->members.raw,
           inst->members.binop, inst->members.operation , inst->members.data);

    printf("\tBITS: ");
    vm_data_print_raw_bits(sizeof inst->members.raw, &inst->members.raw);
}

这是Linux机器上问题顶部的示例ASCII的结果，很好，很花哨！

DEBUG DATA #0 =>  RAW: 16777260     BINCODE: 0  OPCODE: 1   DATA: 44            BITS: 00000001000000000000000000101100
DEBUG DATA #1 =>  RAW: 16777260     BINCODE: 0  OPCODE: 1   DATA: 44            BITS: 00000001000000000000000000101100
DEBUG DATA #2 =>  RAW: -2147483648  BINCODE: 1  OPCODE: 0   DATA: 0             BITS: 10000000000000000000000000000000
DEBUG DATA #3 =>  RAW: 134217728    BINCODE: 0  OPCODE: 8   DATA: 0             BITS: 00001000000000000000000000000000
DEBUG DATA #4 =>  RAW: 167772160    BINCODE: 0  OPCODE: 10  DATA: 0             BITS: 00001010000000000000000000000000

现在，在Windows机器上使用完全相同的代码（我运行Linux的机器）我得到了一个非常不同的结果（我用MinGW和MSVC2015编译）：

DEBUG DATA #0 =>  RAW: 16777260     BINCODE: 1   OPCODE: 77      DATA: 44                BITS: 00000001000000000000000000101100
DEBUG DATA #1 =>  RAW: 16777260     BINCODE: 1   OPCODE: 77      DATA: 44                BITS: 00000001000000000000000000101100
DEBUG DATA #2 =>  RAW: 2147483647   BINCODE: 1   OPCODE: 77      DATA: -1                BITS: 01111111111111111111111111111111
DEBUG DATA #3 =>  RAW: 134217728    BINCODE: 1   OPCODE: 77      DATA: 0                 BITS: 00001000000000000000000000000000
DEBUG DATA #4 =>  RAW: 167772160    BINCODE: 1   OPCODE: 77      DATA: 0                 BITS: 00001010000000000000000000000000

所以问题是，这种差异来自哪里？我该怎么做才能使Windows和Linux之间保持一致？

我已经检查了这个question，但它并没有为我解决这个问题，因为所有已签名或未签名的工会成员仍无法在Windows上运行。

Linux和Windows之间的联合结构不一致（GCC / MSVC）

0 个答案: