向Logistic回归（glm）模型添加多个解释变量会产生错误？

Question

我试图使用以下线性模型：

ad.glm.all <- glm(WinLoss ~  Score + Margin + Opposition + Venue + Disposals + Marks + Goals + Behinds + Hitouts + Tackles + Rebound50s + Inside50s + Clearances + Clangers + FreesFor + ContendedPossessions + ContestedMarks + MarksInside50 + OnePercenters + Bounces+GoalAssists, 
                  data = ad.train, family = binomial)

每次我尝试运行此代码时，都会收到以下错误消息：

glm.fit: algorithm did not convergeglm.fit: fitted probabilities numerically 0 or 1 occurred

当我查看这个回归模型的摘要时，我得到：

Call:
glm(formula = WinLoss ~ Score + Margin + Disposals + Marks + 
    Goals + Behinds + Hitouts + Tackles + Rebound50s + Inside50s + 
    Clearances + Clangers + FreesFor + ContendedPossessions + 
    ContestedMarks + MarksInside50 + OnePercenters + Bounces + 
    GoalAssists, family = binomial, data = ad.train)

Deviance Residuals: 
       Min          1Q      Median          3Q         Max  
-2.980e-05  -2.100e-08   2.100e-08   2.100e-08   3.569e-05  

Coefficients:
                       Estimate Std. Error z value Pr(>|z|)
(Intercept)          -8.578e+00  2.502e+06   0.000        1
Score                 4.194e+00  5.165e+04   0.000        1
Margin                2.187e+00  3.742e+03   0.001        1
Disposals             8.946e-02  3.549e+03   0.000        1
Marks                 1.427e-01  1.938e+03   0.000        1
Goals                -2.288e+01  3.082e+05   0.000        1
Behinds              -7.034e+00  5.482e+04   0.000        1
Hitouts               3.640e-02  5.167e+03   0.000        1
Tackles               8.939e-01  7.075e+03   0.000        1
Rebound50s           -2.064e-01  8.497e+03   0.000        1
Inside50s             5.645e-01  8.133e+03   0.000        1
Clearances           -1.930e-01  1.525e+04   0.000        1
Clangers             -2.040e-01  1.056e+04   0.000        1
FreesFor             -7.699e-01  1.762e+04   0.000        1
ContendedPossessions -5.752e-01  7.424e+03   0.000        1
ContestedMarks       -1.869e+00  1.069e+04   0.000        1
MarksInside50         6.742e-01  1.676e+04   0.000        1
OnePercenters         1.616e-01  6.888e+03   0.000        1
Bounces              -8.763e-01  7.669e+03   0.000        1
GoalAssists           7.570e-01  3.299e+04   0.000        1

(Dispersion parameter for binomial family taken to be 1)

    Null deviance: 1.2540e+02  on 91  degrees of freedom
Residual deviance: 7.1154e-09  on 72  degrees of freedom
AIC: 40

Number of Fisher Scoring iterations: 25

显然这里有些严重错误，对吗？每个变量的P值都不能为1，而我的Z值都为0;正确？

我给了它一个谷歌，我能找到的最好的是有人建议错误可能是由于变量太多（考虑到我有多少变量，这是有意义的）。所以我一个接一个地删除它们，我会仍然每次尝试都会得到错误，直到我只有一个变量（x~y）;只有这样我才能得到错误。

有人可以向我解释这个错误可能意味着什么吗？为什么我的所有P值都是1，z值为0？

提前致谢！

-Troy