例如我的模型有这个代码
g = glm(Vote ~., -ID, data=train, family=binomial)
因此,-ID
排除ID
列。如果我想排除更多列,该怎么办?我试过了
g = glm(Vote ~., -c(ID,YOB,ABC) , data=train, family=binomial)
引发了错误。
答案 0 :(得分:2)
尝试在数据参数中使用否定命名列:
glm(... , data=train[, -c( "ID", "YOB","ABC")], ...)
答案 1 :(得分:2)
?formula
提到您可以使用-
删除字词。方法如下:
glm(Vote ~. -ID, data = train, family = binomial)
g = glm(Vote ~. - ID - YOB - ABC, data = train, family = binomial)
好吧,我可以给你一些例子:
> head(trees) ## this is R's built-in dataset
Girth Height Volume
1 8.3 70 10.3
2 8.6 65 10.3
3 8.8 63 10.2
4 10.5 72 16.4
5 10.7 81 18.8
6 10.8 83 19.7
现在我们建立一个模型,放弃Girth
和Height
:
> lm(Volume ~. -Girth - Height, trees)
Call:
lm(formula = Volume ~ . - Girth - Height, data = trees)
Coefficients:
(Intercept)
30.17
现在你看到只估计了拦截。