Question

抱歉我的英语，但我是意大利人...... 我想创建一个代码，用于计算点（带有两个坐标）是否在具有凹角和凸角的多边形内。我尝试了很少的代码因为太难了..

 var polygon = [ 
  [71.99999994,38.999999714],
  [71.000000057,38.999999714],
  [69.999999998,38.999999714],
  [69.999999998,38.000000007],
  [68.999999939,38.000000007],
  [67.99999988,38.000000007],
  [67.99999988,38.999999714],
  [67.99999988,39.999999597],
  [68.999999939,39.999999597],
  [68.999999939,41.000000008],
  [69.999999998,41.000000008],
  [71.000000057,41.000000008],
  [71.99999994,41.000000008],
  [71.99999994,39.999999597],
  [71.99999994,38.999999714]
 ];

  var point= [68,38.5];

我希望你能帮助我......

非常感谢

Answer 1

算法基于此网站：http://alienryderflex.com/polygon/
它是超快的并处理各种多边形类型。我已将其调整为javascript和您的数据结构。

    function IsPointInPolygon(poly_array, test_point) {
        var inside = false;
        var test_x = test_point[0];
        var test_y = test_point[1];
        for(var i=0; i<(poly_array.length-1); i++) {
            var p1_x = poly_array[i][0];
            var p1_y = poly_array[i][1];
            var p2_x = poly_array[i+1][0];
            var p2_y = poly_array[i+1][1];
            if((p1_y<test_y && p2_y>=test_y) || (p2_y<test_y && p1_y>=test_y)) { // this edge is crossing the horizontal ray of testpoint
                if((p1_x+(test_y-p1_y)/(p2_y-p1_y)*(p2_x-p1_x)) < test_x) { // checking special cases (holes, self-crossings, self-overlapping, horizontal edges, etc.)
                    inside=!inside;
                }
            }
        }
        return inside;
    }

您可以直接使用变量调用它：

    if(IsPointInPolygon(polygon, point)) {
        alert('Inside');
    }
    else {
        alert('Outside');
    }

计算点坐标是否在具有凹凸角度的多边形内？ JavaScript的

1 个答案: