SQL连续行，每行之间具有固定的时间跨度

时间：2017-01-26 22:28:13

标签： sql sql-server common-table-expression window-functions

StackOverflow上的好人，
请非常友好地提供一些帮助...

所以我们这里有一个类似的表...包含客户给某个联络中心（HelpDesk或其他）的电话。

-----------------------------------------------------------------------
|   DateD  |   DateM   |    Date_Time    |EMPL_ID| PHONE_NO |FIRST_REP |
|----------------------------------------------------------------------
|2016-12-12| 2016-12-01| 2016-12-12 15:55| 16652 | 123456789| First    |
|2016-12-22| 2016-12-01| 2016-12-22 10:42| 18178 | 123456789| First    |
|2016-12-22| 2016-12-01| 2016-12-22 10:54|112981 | 123456789| Repeat   |
|2016-12-22| 2016-12-01| 2016-12-22 10:57| 18179 | 123456789| Repeat   |
|2016-12-23| 2016-12-01| 2016-12-23 12:27| 16653 | 123456789| Repeat   |
|2017-01-05| 2017-01-01| 2017-01-05 15:20| 17896 | 123456789| First    |
|2017-01-11| 2017-01-01| 2017-01-11 15:48| 17909 | 123456789| Repeat   |
|2017-01-18| 2017-01-01| 2017-01-18 10:07| 18175 | 123456789| Repeat   |
|2016-12-03| 2016-12-01| 2016-12-03 20:32| 17745 | 111222333| First    |
|2016-12-21| 2016-12-01| 2016-12-21 18:47| 10982 | 111222333| First    |
|2016-12-22| 2016-12-01| 2016-12-22 15:53| 17820 | 111222333| Repeat   |
|2016-12-28| 2016-12-01| 2016-12-28 13:07| 15976 | 111222333| Repeat   |
|2016-12-29| 2016-12-01| 2016-12-29 21:35| 17896 | 111222333| Repeat   |
|2016-12-29| 2016-12-01| 2016-12-29 21:46| 15498 | 111222333| Repeat   |
|2017-01-02| 2017-01-01| 2017-01-02 16:24| 13117 | 111222333| Repeat   |
-----------------------------------------------------------------------

我想做的是弄清楚，重复了多少次来电，这意味着客户再次打来电话。

现在棘手的部分是重复呼叫被定义为源自“第一次呼叫”的呼叫，并且在第一次呼叫之后的每次交互的7天时间内连续重复，例如：

----------------------------------------------------------------------------
|   DateD   |    DateM   |    Date_Time     |EMPL_ID|  PHONE_NO |FIRST_REP |
|---------------------------------------------------------------------------
|2016-12-01 | 2016-12-12 | 2016-12-12 15:55 | 16652 | 123456789 | First    |
|2016-12-01 | 2016-12-22 | 2016-12-22 10:42 | 18178 | 123456789 | First    |
|2016-12-01 | 2016-12-22 | 2016-12-22 10:54 | 112981| 123456789 | Repeat   |
|2016-12-01 | 2016-12-22 | 2016-12-22 10:57 | 18179 | 123456789 | Repeat   |
|2016-12-01 | 2016-12-23 | 2016-12-23 12:27 | 16653 | 123456789 | Repeat   |
|2017-01-01 | 2017-01-05 | 2017-01-05 15:20 | 17896 | 123456789 | First    |
|2017-01-01 | 2017-01-11 | 2017-01-11 15:48 | 17909 | 123456789 | Repeat   |
|2017-01-01 | 2017-01-18 | 2017-01-18 10:07 | 18175 | 123456789 | Repeat   |
----------------------------------------------------------------------------

我们有：
第一行是没有重复呼叫的第一次呼叫，
2sd行是第一次呼叫，有3次重复呼叫，因为每次互动都是在从第一次呼叫开始的每个前一天7天的时间跨度内 第3行是第一次通话，有2次重复通话，如上所述。

现在我们要说的是ID为16652的员工（第1行）产生了0次重复呼叫，但另一方面生成了ID 18178的员工3次重复呼叫。

最后，有一些方法可以创建像这样的输出：

|   DateM   |    DateD   |     Date_Time    |EMP_ID |  PHONE_NO |FIRST_REP | DateM_REP  | DateD_REP  | Date_Time_REP    | EMP_ID_REP | PHONE_NO_REP | FIRST_REP_REP
|------------------------------------------------------------------------------------------------------------------------------------------------------------------|
|2016-12-01 | 2016-12-12 | 2016-12-12 15:55 | 16652 | 123456789 |   First  |    null    |    null    |       null       |   null     |    null      | null
|2016-12-01 | 2016-12-22 | 2016-12-22 10:42 | 18178 | 123456789 |   First  | 2016-12-01 | 2016-12-22 | 2016-12-22 10:54 |   112981   |   123456789  | Repeat
|2016-12-01 | 2016-12-22 | 2016-12-22 10:42 | 18178 | 123456789 |   First  | 2016-12-01 | 2016-12-22 | 2016-12-22 10:57 |   18179    |   123456789  | Repeat
|2016-12-01 | 2016-12-22 | 2016-12-22 10:42 | 18178 | 123456789 |   First  | 2016-12-01 | 2016-12-23 | 2016-12-23 12:27 |   16653    |   123456789  | Repeat
|2017-01-01 | 2017-01-05 | 2017-01-05 15:20 | 17896 | 123456789 |   First  | 2017-01-01 | 2017-01-11 | 2017-01-11 15:48 |   17909    |   123456789  | Repeat
|2017-01-01 | 2017-01-05 | 2017-01-05 15:20 | 17896 | 123456789 |   First  | 2017-01-01 | 2017-01-18 | 2017-01-18 10:07 |   18175    |   123456789  | Repeat

请帮忙，我不擅长写CTE，因为我认为这是一个有可能通过CTE解决的问题。

很多人不屑一顾 卢基的

编辑：

CREATE TABLE t_calls
(
[DateM] date,
[DateD] date,
[Date_Time] datetime2(7),
[EMPL_ID] int,
[INTERACTION_ID] numeric(25,0),
[PHONE_NO] numeric(9,0),
[FIRST_REP] varchar(10)
)

Insert Into t_calls

([DateM],[DateD],[Date_Time],[EMPL_ID],[INTERACTION_ID],[PHONE_NO],[FIRST_REP])
Values 
('2016-12-01 00:00:00','2016-12-12 00:00:00','2016-12-12 15:55:36',16652,340680165,123456789,'First')
,('2016-12-01 00:00:00','2016-12-22 00:00:00','2016-12-22 10:42:45',18178,343736497,123456789,'First')
,('2016-12-01 00:00:00','2016-12-22 00:00:00','2016-12-22 10:54:46',112981,343750151,123456789,'Repeat')
,('2016-12-01 00:00:00','2016-12-22 00:00:00','2016-12-22 10:57:29',18179,343750151,123456789,'Repeat')
,('2016-12-01 00:00:00','2016-12-23 00:00:00','2016-12-23 12:27:56',16653,344071359,123456789,'Repeat')
,('2017-01-01 00:00:00','2017-01-05 00:00:00','2017-01-05 15:20:47',17896,347063121,123456789,'First')
,('2017-01-01 00:00:00','2017-01-11 00:00:00','2017-01-11 15:48:20',17909,348429965,123456789,'Repeat')
,('2017-01-01 00:00:00','2017-01-18 00:00:00','2017-01-18 10:07:45',18175,350243945,123456789,'Repeat')
,('2016-12-01 00:00:00','2016-12-03 00:00:00','2016-12-03 20:32:37',17745,338392721,111222333,'First')
,('2016-12-01 00:00:00','2016-12-21 00:00:00','2016-12-21 18:47:12',10982,343633967,111222333,'First')
,('2016-12-01 00:00:00','2016-12-22 00:00:00','2016-12-22 15:53:59',17820,343885389,111222333,'Repeat')
,('2016-12-01 00:00:00','2016-12-28 00:00:00','2016-12-28 13:07:19',15976,344944219,111222333,'Repeat')
,('2016-12-01 00:00:00','2016-12-29 00:00:00','2016-12-29 21:35:44',17896,345396945,111222333,'Repeat')
,('2016-12-01 00:00:00','2016-12-29 00:00:00','2016-12-29 21:46:43',15498,345398005,111222333,'Repeat')
,('2017-01-01 00:00:00','2017-01-02 00:00:00','2017-01-02 16:24:12',13117,346045147,111222333,'Repeat')

1 个答案:

答案 0 :(得分：0)

如果我理解您的问题，您希望每次通话都知道什么，请在7天内重复多少次通话。

SELECT
  a.date_time
  ,a.emp_id
  ,a.phone_no
  ,count(b.phone_no) as repeat_calls  --count any non-null field
  ,min(b.date_time) as first_repeat_call_at
FROM t_calls a
LEFT JOIN t_calls b
  ON a.phone_no = b.phone_no  --same phone
    AND datediff(d, a.date_time, b.date_time) between 0 AND 6 --a repeat comes in today + 6 days
    AND a.date_time < b.date_time  --prevents self join
GROUP BY
  a.date_time
  ,a.emp_id
  ,a.phone_no

对于任何0次重复的调用，没有什么可以加入，因此无需计算，因此repeat_calls = 0且first_repeat_call_at为NULL。

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