SQL每行可用的连续日期

Question

如何使用SQL创建查询以使每一行连续一天可用。例如，我想连续3天找到至少3个可用房间

原始表

Date       Available rooms 
----       ---------------
01/12/16         4
02/12/16         5
03/12/16         5
04/12/16         5
05/12/16         4
06/12/16         0
07/12/16         3
08/12/16         4
09/12/16         4

结果低于

Date      EndDate       
--------  --------
01/12/16  03/12/16
02/12/16  04/12/16
03/12/16  05/12/16
07/12/16  09/12/16

Answer 1

尝试使用LEAD（）函数，如下面的查询

SELECT d as StartDate, EndDate
FROM
    (SELECT d, 
        CASE 
            WHEN available_rooms > 2 
                AND LEAD(available_rooms,1) OVER(order by d) > 2 
                AND LEAD(available_rooms,2) OVER(order by d) > 2 
            THEN LEAD(d,2) OVER(order by d) 
        END EndDate
    FROM table1 t) t1
WHERE EndDate is not null;

以下是我收到的输出

Answer 2

<强> SQL DEMO

SELECT T1.[Date], T3.[Date]
FROM Table1 T1
JOIN Table1 T2
  ON T1.[Date] = DATEADD(day, -1, T2.[Date])
JOIN Table1 T3
  ON T1.[Date] = DATEADD(day, -2, T3.[Date])
WHERE T1.[Available rooms] >= 3
  AND T2.[Available rooms] >= 3
  AND T3.[Available rooms] >= 3

<强>输出