Question

我正在尝试计算n角形状的点之间的角度。有2个数组，它们包含x和y坐标。我不断收到P13的错误，我无法弄清楚原因。有谁知道原因吗？

public class Ugao {

    public static int nizovi(double[]a , double[]b , double alfa) {
        int BrStr = 0;
        for (int i = 0; i < b.length; i++) {
            double P12,P13, P23;
            P12 = duzina(a[i+1], b[i+1], a[i], b[i]);
            P13 = duzina(a[i+1], b[i+1], a[i+2], b[i+2]); // pisemo prvo i+1 jer je to vertex tacka, ona koja je u centru ugla, zato nije od i
            P23 = duzina(a[i], b[i], a[i+2], b[i+2]);

            double x = ugao(P12, P13, P23);
            if(x > alfa) {
                System.out.print( "Stranica : " + "( " + a[i] + "," + b[i] + " )" + "( " + a[i+1] + "," + b[i+1] + " )" + " & ");
                System.out.println("( " + a[i+1] + "," + b[i+1] + " )" + "( " + a[i+2] + "," + b[i+2] + " )");
                System.out.println();
                BrStr++;
            }
        }
        return BrStr;
    }


    public static double ugao (double P12, double P13, double P23) {
        return Math.acos((Math.pow(P12, 2) + Math.pow(P13, 2) - Math.pow(P23, 2))/(2 * P12 * P13));
    }

    public static double duzina (double vertexX1, double vertexY1, double x2, double y2) {
        return  Math.sqrt(Math.pow((vertexX1-x2),2)+ Math.pow((vertexY1-y2), 2));
    }

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        double a[] = {12,25,3};
        double b[] = {11,20,5};

        nizovi(a, b, 45);

    }

}

Answer 1

您的阵列范围已用完。

例如，如果length = 4数组包含索引0..3，但在最后一个循环中使用i=3表达式a[i+2]需要元素a[5]

您可以使用模运算来获取下一个顶点索引

 current: i
 next: (i+1)%length
 nextnext: (i+2)%length

计算n角的角度（加上比较）

1 个答案: