Question

使用python评分学生成绩。试图简化

A = ((float(scptratio)) >= (0.9) and (float(scptratio) <= 1))
B = ((float(scptratio)) >= (0.8) and (float(scptratio) <= (0.89)))

if A == True:
print (studentname, (" has scored an A on the test."))

elif B == True:
print (studentname, (" has scored an B on the test."))

elif C == True:
    print (studentname, (" has scored an C on the test."))

等。

的内容

A = (((float(scptratio)) >= (0.9) and (float(scptratio) <= 1)), "A")
B = (((float(scptratio)) >= (0.8) and (float(scptratio) <= (0.89))), "B")

Pass = [A, B, C, D]


if Pass:
    print (studentname, "passed the test with a coefficient of", scptratio, ("scoring a grade of {}".format(Pass)))
elif F:
    print (studentname, "has failed the test.")

else:
    print ("Error! Negative value entered.")

如何让它打印实际的字母分数而不是布尔值？

Answer 1

我建议制作一个易于编辑的列表，其中包含特定成绩所需的最低分数，从高到低：

minimum_scores = [("A", 9), ("B", 8), ("C", 7), ("D", 6)]

然后浏览此列表并打印学生通过的一年级。

for grade, score in minimum_scores:
    if float(scptratio) >= score:
        print(studentname, "passed the test with a coefficient of", str(scptratio), "scoring a grade of", grade)
        break
else: #No break hit, so the student didn't pass any of the minimum requirements.
    print(studentname, "has failed the test.")

简化，打印文本而不是布尔值，Python

1 个答案: