Question

所以这是挑战：

我需要按照以下示例更新表格中特定列的字符串：

例1：
来自：texttext / 21/812 / 21a
收件人：texttext-21a81221
例2：
来自：texttext / 6/163 / 38a
收件人：texttext-38a1636

“texttext”长度可能会有所不同，也可能包含斜杠（/）。

此外，数字的块2和块3不能有2位数。

所以，

texttext / 53 / 7A / A2

必须变成：

texttext-0a207a53

我正在使用SQL Server 2008。

感谢您帮助我的努力。

谢谢！

Answer 1

不确定你对block 2 and block 3 of numbers can’t have 2 digits的意思无论如何，下面应该给你一个想法

WITH data AS
(
    select Value, REVERSE(Value) AS ReverseValue from (values
        ('texttext/21/812/21a'), ('texttext/6/163/38a'), ('texttext/53/7a/a2'), ('text/t/e/xt/53/7a/a2')
    )t(Value)
), split AS
(
    select 
        Value, ReverseValue, 
        reverse(substring(ReverseValue, 1, P1.Pos - 1)) AS Forth,
        reverse(substring(ReverseValue, P1.Pos + 1, P2.Pos - P1.Pos - 1)) AS Third,
        reverse(substring(ReverseValue, P2.Pos + 1, P3.Pos - P2.Pos - 1)) AS Second,
        reverse(substring(ReverseValue, p3.Pos + 1, len(ReverseValue))) AS First
    from data       
        cross apply (select (charindex('/', ReverseValue))) as P1(Pos)
        cross apply (select (charindex('/', ReverseValue, P1.Pos+1))) as P2(Pos)
        cross apply (select (charindex('/', ReverseValue, P2.Pos+1))) as P3(Pos)
)
select Value, First + '-' + Forth + Third + Second AS NewValue from split

如何解决这个字符串算法？

1 个答案: