json_from_db:
{
"id": 23,
"positions": "[{\"col\":2,\"row\":1,\"size_x\":10,\"size_y\":3}]",
"styles": "\"position: absolute; min-width: 135px; min-height: 160px;\"",
"created_at": "2016-07-18 02:40:36",
"updated_at": "2016-07-18 02:40:36"
}
在PHP中循环:
$positions = json_from_db
foreach($positions->position as $value) { echo $value->col}
提供的参数无效错误
我想得到col,sixe_x和size_y
的值更新
下面的答案是正确的,但是 想要获得风格的价值
答案 0 :(得分:1)
试试我的xD源码
$positions = json_decode('{
"id": 6,
"positions": [
{
"col": 6,
"row": 1,
"size_x": 2,
"size_y": 2
}
],
"created_at": "2016-07-17 23:36:47",
"updated_at": "2016-07-17 23:36:47"
}');
echo 'col: '.$positions->positions[0]->col.'<br>';
echo 'row: '.$positions->positions[0]->row.'<br>';
echo 'size_x: '.$positions->positions[0]->size_x.'<br>';
echo 'size_y: '.$positions->positions[0]->size_y.'<br>';
您将获得结果
col: 6
row: 1
size_x: 2
size_y: 2
答案 1 :(得分:1)
您需要使用json_decode()
。
$arr = '{"id":6,"positions":" [{\"col\":6,\"row\":1,\"size_x\":2,\"size_y\":2}]","created_at":"2016-07-17 23:36:47","updated_at":"2016-07-17 23:36:47"}';
$positionsArr = json_decode($arr,true);
$positions = json_decode($positionsArr["positions"],true);
foreach($positions as $value)
{
echo "size x:". $value['size_x']. "\n size y: ". $value['size_y'];
}
现场演示:Click Here
答案 2 :(得分:1)
您需要先解码JSON才能使用数据
$json_obj = json_decode($json_from_db);
$positions = $json_obj->positions;
foreach($positions as $position){
echo $position->col . "<br/>";
}