{
"data":[
{
"name":"JIN",
"id":"100007934492797"
},
{
"name":"aris",
"id":"100008128873664"
},
{
"name":"Madm",
"id":"34234234"
}
],
"paging":{
"next":"https://graph.facebook.com/v1.0/1380314981/friends?limit=5000&offset=5000&__after_id=enc_AeyRMdHJrW0kW9vIZ41uFPXMPgE-VwRaHtQJz2JWyVc0hMl9eOG10C6JWjoCO8O2E4m24EPr28gIt9mxQR8oIQmN"
}
}
我想在db中存储我的json的名称和ID。但是当我使用for循环时,偏移有问题,我怀疑它是json的最后一部分。如何删除分页部分?我试过了
foreach($friends as friend){
echo friend[0]->name;
}
答案 0 :(得分:0)
首先,您的原始代码永远不会起作用:
foreach($friends as friend){
echo friend[0]->name;
}
对friend
的引用应该在他们面前$
制作$friend
。然后,要解决更大的问题,只需使用嵌套的foreach
循环:
$json = <<<EOT
{
"data": [
{
"name": "JIN",
"id": "100007934492797"
},
{
"name": "aris",
"id": "100008128873664"
},
{
"name": "Madm",
"id": "34234234"
}
],
"paging": {
"next": "https://graph.facebook.com/v1.0/1380314981/friends?limit=5000&offset=5000&__after_id=enc_AeyRMdHJrW0kW9vIZ41uFPXMPgE-VwRaHtQJz2JWyVc0hMl9eOG10C6JWjoCO8O2E4m24EPr28gIt9mxQR8oIQmN"
}
}
EOT;
$friends = json_decode($json);
foreach($friends as $friend_data){
foreach($friend_data as $friend){
echo $friend->name . '<br />';
}
}
这个的输出是:
JIN
aris
Madm
此外,如果使用数组对您更有意义,您可以通过将第二个参数设置为json_decode
来设置true
以返回数组。以下是重构代码示例:
$friends = json_decode($json, true);
foreach($friends as $friend_data){
foreach($friend_data as $friend_key => $friend_value){
if (isset($friend_value['name'])) {
echo $friend_value['name'] . '<br />';
}
}
}