Question

$query = "SELECT * from tblTwigUsers;";
    $result = mysqli_query ($con,$query);

if (mysqli_num_rows($result)>0)
    {
        $response = array();
        $code = "profile_true";
        while($row = mysqli_fetch_array($result))
        {
            array_push    ($response,array("code"=>$code,"fldUser_Id"=>$row[0],"fldUser_UserName"=>$row[2]));   
            echo json_encode(array("server_resposnse"=>$response));
        }
    }
else
    {   
        $response = array();
        $code = "profile_false";
        $message = "failed to get user profile info...";
        array_push ($response,array("code"=>$code,"message"=>$message));
        echo json_encode(array("server_resposnse"=>$response));  
    }

结果

    {
    "server_resposnse": [{
        "code": "profile_true",
        "fldUser_Id": "1",
        "fldUser_UserName": "sohan"
    }]
} {
    "server_resposnse": [{
        "code": "profile_true",
        "fldUser_Id": "1",
        "fldUser_UserName": "sohan"
    }, {
        "code": "profile_true",
        "fldUser_Id": "2",
        "fldUser_UserName": "sonal"
    }]
} {
    "server_resposnse": [{
        "code": "profile_true",
        "fldUser_Id": "1",
        "fldUser_UserName": "sohan"
    }, {
        "code": "profile_true",
        "fldUser_Id": "2",
        "fldUser_UserName": "sonal"
    }, {
        "code": "profile_true",
        "fldUser_Id": "3",
        "fldUser_UserName": "amit"
    }]
} {
    "server_resposnse": [{
        "code": "profile_true",
        "fldUser_Id": "1",
        "fldUser_UserName": "sohan"
    }, {
        "code": "profile_true",
        "fldUser_Id": "2",
        "fldUser_UserName": "sonal"
    }, {
        "code": "profile_true",
        "fldUser_Id": "3",
        "fldUser_UserName": "amit"
    }, {
        "code": "profile_true",
        "fldUser_Id": "4",
        "fldUser_UserName": "rajiv"
    }]
}

为什么数据重复？第四个结果是正确的，我需要吗？怎么弄？帮助赞赏，

THX， Sohan

Answer 1

不要在循环中echo json_encode()，因为那样你会多次打印JSON，每一个都比前一个稍长一些。等到循环完成后。

$response = array();
if (mysqli_num_rows($result)>0)
{
    $code = "profile_true";
    while($row = mysqli_fetch_array($result))
    {
        array_push($response,array("code"=>$code,"fldUser_Id"=>$row[0],"fldUser_UserName"=>$row[2]));   
    }
}
else
{   
    $code = "profile_false";
    $message = "failed to get user profile info...";
    array_push($response,array("code"=>$code,"message"=>$message)); 
}
echo json_encode(array("server_resposnse"=>$response));

顺便说一下，你拼错了＃34;回复＆＃34;在"server_responsnse"。确保在此处以及处理JSON的代码中使用相同的拼写。

此外，array_push($array, $value);可以更加惯用地编写为$array[] = $value;

循环通过..array推入php

1 个答案: