我有一个输出数组如下。我想遍历数组,以便我可以一次获得一个文件元素。即一个图像元素及其详细信息。
我尝试了很多但是无法做到。
Array
(
[name] => Array
(
[0] => stock-photo-cup-icons-tea-and-coffee-raster-version-109119257.jpg
[1] => tea-cup-icon.png
[2] => tea.png
[3] => stock-vector-vector-black-tea-icons-set-all-white-areas-are-cut-away-from-icons-and-black-areas-merged-81392851.jpg
)
[type] => Array
(
[0] => image/jpeg
[1] => image/png
[2] => image/png
[3] => image/jpeg
)
[tmp_name] => Array
(
[0] => D:\xampp\tmp\php6BB.tmp
[1] => D:\xampp\tmp\php6BC.tmp
[2] => D:\xampp\tmp\php6BD.tmp
[3] => D:\xampp\tmp\php6BE.tmp
)
[error] => Array
(
[0] => 0
[1] => 0
[2] => 0
[3] => 0
)
[size] => Array
(
[0] => 30609
[1] => 3615
[2] => 8966
[3] => 23117
)
)
答案 0 :(得分:2)
你的意思是什么?
$images = array();
foreach( $array as $key=>$values ){
foreach( $values as $no=>$value ){
$images[$no][$key] = $value;
}
}
答案 1 :(得分:1)
你可以这样做,虽然很糟糕!
for ($i = 0; $i < count($array["name"]); $i++)
{
echo $array["name"][$i], $array["type"][$i], $array["size"][$i];
}
注意:这仅适用于此类顺序数组。这不适用于具有关联索引的数组。
答案 2 :(得分:0)
你只需循环遍历数组
$count = 0;
foreach ($_FILES['fileField']['name'] as $filename)
{
$file = $_FILES['fileField']['name'][$count];
$type = $_FILES['fileField']['type'][$count];
$size = $_FILES['fileField']['size'][$count];
$count++;
}
答案 3 :(得分:0)
我会做这样的事情:
$fileDetais = array();
foreach($arr["name"] as $id => $fname) {
$fileDetais["name"] = $fname;
$fileDetais["type"] = $arr["type"][$id];
$fileDetais["tmp_name"] = $arr["tmp_name"][$id];
$fileDetais["error"] = $arr["error"][$id];
$fileDetais["size"] = $arr["size"][$id];
//now you have all info about one file in $fileDetais
}