Question

我正在尝试遍历我发布到PHP后端的JSON。 JSON看起来像这样：

UPDATE UserAnswer 
SET userId = (SELECT TOP(1) id FROM Users Order By id DESC) 
WHERE userId = NULL

我是这样从邮差发布的：

我希望能够使用

打印我单独发布的每个号码

[
    {
        "number":"5613106"
    },
    {
        "number":"56131064" 
    },
    {
        "number":"56131063" 
    }
]

现在，当我使用以下内容时，它只打印最后一个数字：

echo $number;

我的功能：

$number = $json['number'];
echo $number;

输出：

public function check_users_post()
{
    $json = $this->request->body;
    print_r($json);
    $this->response($json, REST_Controller::HTTP_OK);
}

Answer 1

希望这个通用迭代器能帮到你。

$jsonIterator = new RecursiveIteratorIterator(
        new RecursiveArrayIterator(json_decode($json, TRUE)),
        RecursiveIteratorIterator::SELF_FIRST);


foreach ($jsonIterator as $key => $val) {
    if(is_array($val)) {
        echo "$key:\n";
    } else {
        echo "$key => $val\n";
    }
}

Answer 2

使用

json_decode()

PHP内置函数，用于将json解码回PHP变量或数组，然后遍历每个索引并打印数字。

Answer 3

这样做：

public function check_users_post()
{
    $json = $this->request->body;

    $jsonIterator = new RecursiveIteratorIterator(
        new RecursiveArrayIterator($json),
        RecursiveIteratorIterator::SELF_FIRST);

    $phone_numbers = "";

    foreach ($jsonIterator as $key => $val) {
        if(is_array($val)) {

        } else {
            $phone_numbers = "$phone_numbers" . ", " . "$val";
        }
    }

    $phone_numbers = substr($phone_numbers, 2);
    $phone_numbers = "(" . $phone_numbers . ")";

    $query = $this->db->query("SELECT * FROM users WHERE user_number in $phone_numbers;");
    $result = $query->result();
    $this->response($result, REST_Controller::HTTP_OK);

    if (mysql_num_rows($result)==0) {
        $data = [ 'message' => 'No users returned'];
        $this->response($data, REST_Controller::HTTP_BAD_REQUEST);
    } else {
        $this->response($result, REST_Controller::HTTP_OK);
    }
}

Answer 4

<强>描述

首先对你的JSON进行字符串化，而不是使用JSON_DECODE（）函数，该函数为你提供数组，然后使用foreach循环对这个数组进行迭代，这将为你提供你想要回应的每个键。

<强>代码

             $str = '[
                  {
                   "number":"5613106"
                  },
                  {
                   "number":"56131064"  
                  },
                  {
                   "number":"56131063"  
                  }
               ]';
            $array = json_decode($str, true);
            echo "<pre>";
            foreach ($array as $key => $key_value) { // then loop through it
                echo "<br>";
                echo $array[$key]['number'];
                echo "<br>";
           }

<强>输出

在PHP中循环使用JSON

4 个答案: