我想绘制一条连接屏幕上三个点的曲线 PointA =(480,46) PointB =(160,137) PointC =(0,228)
如何使用Android API绘制曲线?
请帮助..
谢谢,
森
答案 0 :(得分:13)
无论我想要什么,我都可以使用以下代码制作它:
protected void onDraw(Canvas canvas) {
super.onDraw(canvas);
PointF mPoint1 = new PointF(w/1.2F, h/1.2F);
PointF mPoint2 = new PointF(w/24, h/1.2F);
Path myPath1 = new Path();
Paint paint = new Paint();
paint.setAntiAlias(true);
paint.setStyle(Style.STROKE);
paint.setStrokeWidth(2);
paint.setColor(Color.WHITE);
myPath1 = drawCurve(canvas, paint, mPoint1, mPoint2);
canvas.drawPath(myPath1, paint);
}
private Path drawCurve(Canvas canvas, Paint paint, PointF mPointa, PointF mPointb) {
Path myPath = new Path();
myPath.moveTo(63*w/64, h/10);
myPath.quadTo(mPointa.x, mPointa.y, mPointb.x, mPointb.y);
return myPath;
}
这将找到屏幕的两侧(风景模式),并在屏幕上绘制完美的曲线。