Question

我一直试图使用正确的模拟摇杆创建延迟旋转效果。下面的代码采用基于右模拟杆输入的角度，使对象稳定地靠近。由于atan2是-pi到pi的范围，变化的旋转总是有利于移动通过0弧度而不是pi。有没有办法使角度向相反方向移动？

    private void Angle()
    {
        //Angle to go to
        RotationReference = -(float)(Math.Atan2(YR, XR));

        //Adds on top of rotation to steadily bring it closer
        //to the direction the analog stick is facing
        Rotation += (RotationReference - Rotation) * Seconds *15;
        Console.WriteLine(RotationReference);
    }

编辑：

我尝试使用InBetween建议的方法，该方法导致2pi到0之间的过渡问题。这导致我尝试别的东西。我不知道为什么它不起作用。

    private void Angle()
    {
        //Angle to go to
        RotationReference = -(float)(CorrectedAtan2(YR, XR));

        //Adds on top of rotation to steadily bring it closer
        //to the direction the analog stick is facing
        if (Math.Abs(RotationReference - Rotation) > Math.PI)
            Rotation += ((float)(RotationReference + Math.PI * 2) - Rotation) * Seconds * 15;
        else Rotation += (RotationReference - Rotation) * Seconds *15;
        Console.WriteLine(RotationReference);
    }

    public static double CorrectedAtan2(double y, double x)
    {
        var angle = Math.Atan2(y, x);
        return angle < 0 ? angle + 2 * Math.PI: angle;
    }

这背后的想法是，如果你需要超过180度的行程，你将使角度行进到360度以上。这样就不需要改变方向了。

Answer 1

只需更正适合[0, 2·pi]范围的角度：

public static double CorrectedAtan2(double y, double x)
{
    var angle = Math.Atan2(y, x);
    return angle < 0 ? angle + 2 * Math.PI : angle;
}

Answer 2

经过一些实验，我设法让它发挥作用。感谢InBetween为CorrectedAtan2方法。 for循环用于遍历所有需要添加pi的实例，以避免震动过渡。

    private float Angle(float y, float x)
    {
        //Angle to go to
        RotationReference = -(float)(CorrectedAtan2(y, x));

        for (int i = 0; i < 60; i++)
        {
            if (Math.Abs(RotationReference - Rotation) > Math.PI)
                RotationReference = -(float)(CorrectedAtan2(y, x) +
                    (Math.PI * 2 * i));
        }
        //Adds on top of rotation to steadily bring it closer
        //to the direction the analog stick is facing
        return Rotation += (RotationReference - Rotation) * Seconds * 15;
    }

    public static double CorrectedAtan2(double y, double x)
    {
        var angle = Math.Atan2(y, x);
        return angle < 0 ? angle + 2 * Math.PI: angle;
    }

使用atan2进行延迟旋转

2 个答案: