Question

我想在没有除法运算符的情况下划分数字

def divede_me(val,ded)
    i = 1; new_num=0
    rem = val % ded
    val = val - rem
    while (val != new_num)
        i += 1      
        new_num = ded * i       
    end 
    return i
end

p divede_me(14,4)

上面的脚本返回3但我也想要浮点数（例如3.5）以及编写上述脚本的最佳方法。

Answer 1

def divide_me(val,ded)
    i = 1; new_num=0
    rem = val.to_f % ded
    val = val - rem
    while (val != new_num)
        i += 1
        new_num = ded * i
    end
    temp = 0.01
    temp += 0.01 until ded * temp >= rem
    return i + temp.round(2)
end

p divide_me(14,4)
=>3.5
p divide_me(15,4)
=>3.75
p divide_me(16,7)
=>2.29

扩展现有代码，这将使您获得相当准确的2位小数。删除.round（2）以查看不准确的浮动。

Answer 2

这个逻辑可以帮到你

val = 14
ded = 4

r = val % ded
value = val -r

v_ck = 0
i = 0
while( value != v_ck ) 

    i+=1
    v_ck =  ded * i
end

ded_ck = 0
j = 0
while(ded_ck != ded)    
   j += 1 
   ded_ck = r * j
end

puts  i.to_s+"."+j.to_s

使用ruby划分不使用除运算符的数字

2 个答案: